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muminat
4 years ago
7

The air in this room consists of countless tiny, independent molecules. You can be sure that these air molecules won't all shift

spontaneously to the other side of the room (leaving you in a vacuum) because that would
(A) violate Newton's laws of motion.
(B) be extremely unlikely and therefore violate the 2nd law of thermodynamics.
(C) violate Bernoulli's equation.
(D) not conserve energy and therefore violate the 1st law of thermodynamics.
Physics
1 answer:
beks73 [17]4 years ago
8 0

Answer:

(B) be extremely unlikely and therefore violate the 2nd law of thermodynamics.

Explanation:

This process is highly unlikely and if happens would violet the 2nd law of thermodynamics.

The laws of motion do not rule out a move to one side of the room of all the air molecules. But it would be extremely unlikely to happen that. The second law of thermodynamics states that the universe responds to circumstances that become more and more likely, not improbable.

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An object is dropped from a height of 50 meters. Ignoring air resistance, how long doe take to hit the ground?
Arte-miy333 [17]

here given that object is dropped from height h = 50 m

So here we can say

initial speed is ZERO

acceleration is due to gravity

now in order to find time to reach the ground we can use kinematics

y = v_i*t + \frac{1}{2}at^2

now plug in all values in it

50 = 0 + \frac{1}{2} \times 9.8(t^2)

t = 3.2 s

so it will take 3.2 s to reach the ground

3 0
3 years ago
Find the magnitude of the torque that acts on the molecule when it is immersed in a uniform electric field of 6.19×105 N/C with
Ivan

Answer:

\tau=5.81\times 10^5p\ N-m

Explanation:

We have,

Electric field, E=6.19\times 10^5\ N/C

The electric dipole vector at an angle of 69.9 degrees from the direction of the field.

The torque acting on a molecule is given by :

\tau=p\times E\\\\\tau=pE\sin\theta

p is electric dipole moment

\tau=p\times 6.19\times 10^{5}\times \sin (69.9)\\\\\tau=5.81\times 10^5p\ N-m

So, the magnitude of the torque acting on the molecule is 5.81\times 10^5p\ N-m.

7 0
4 years ago
An object moves with velocity v(t)=t^2-8t+7
solong [7]
<span>a) write a polynomial expression for the position of the particle at any time t greater or equal to zero. 
</span>Position is found by integrating velocity: 

<span>s(t) = (t^3)/3 - 4t^2 + 7t + c 
</span>where c is a constant corresponding to the position at t=0. <span>

b) at what time(s) is the particle changing direction
</span>the particle changes direction whenever the velocity is zero; the velocity function equals 

<span>(t-1)(t-7) a difference of squares so the zeros are 1 and 7, it changes direction at 1 second and 7 seconds. </span><span>

c) find the total distance traveled by the particle from t=0 and t=4
</span><span>s(0) = c
s(1) = 8/3 + c
s(4) = 64/3 - 64 + 28 + c. 
</span>
from 0 to 1 the particle travels 8/3 units. From 1 to 4 it travels -(64/3 - 36 - 8/3) = (-(56/3 - 108/3)) 
<span>=-(-52/3) = 52/3 units 
</span>
<span>so in total it travels 52/3 + 8/3 =20 units</span>
6 0
3 years ago
in positive numbers less than 1, the zeros between the decimal point and non zero are _____ significant ​
Margaret [11]
Zeros the left of the decimal but still less than one are non significant but to the right they are.
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8 0
3 years ago
Find the force needed to lift a 3000 N weight using a machine with a mechanical advantage of 15.
Soloha48 [4]

IF the machine is 100% efficient, then you only need to push at the input with a force of 200 Newtons. BUT ... you have to keep pushing the 200N 15 times as far as you want to lift the big weight.

8 0
3 years ago
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