Question

A scallop forces open its shell with an elastic material called abductin whose elastic modulus is about 2.5× 10% N/m2 . If this piece of abductin is 3.0 mm thick and has a cross sectional area of 0.50 cm2 , how much potential energy does it store when compressed 1.0 mm?

Answer 1

Answer:

U= 4.1×10^{-3} J

Explanation:

Given:

Young's modulus E= 2.5×10^5 N/m^2

thickness of material L_o =3.0 mm

Area A= 0.50 cm^2

ΔL= 1.0 cm

The potential energy is given by

U= 1/2FΔx

$F = \frac{EA}{Lo}\Delta L$

therefore

$U=\frac{1}{2}\frac{EA}{Lo}\Delta L^2$

now putting values we get

$U=\frac{1}{2}\frac{2.5\times10^5\times0.5\times10^{-4}}{3\times10^{-3}}\Delta (1\times10^{-3})^2$

U= 4.1×10^{-3} J