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insens350 [35]
3 years ago
6

If the center of mass passes outside the area of support of an object, what will happen to it?

Physics
1 answer:
defon3 years ago
6 0

Answer:

If a vertical line extending down from an object's CG extends outside its area of support, the object will topple

Explanation:

We can understand better this situation using a diagram with the forces acting on it.

In the attached image we can see that when the gravity center is bouncing outside from the area of the pedestal, the object will be out of balance and will fall.

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2. Compare and contrast light microscopes, electron microscopes,<br> and atomic force microscopes.
IRINA_888 [86]

Answer:

Answer is the explanation.

Explanation:

A light microscope (LM) is an instrument which uses the visible light and magnifying glasses to examine small objects that are invisible to the naked eye or have finer details than the naked eye allows. However, magnification is not the main problem in microscopy.

Electron microscopy (EM) is a technique for obtaining high-resolution images of biological and non-biological samples. It is used in biomedical research to study the detailed structure of tissues, cells, organelles and macromolecular complexes.

An atomic force microscope is a type of high-resolution scanning probe microscope with a resolution that can be measured in fractions of a nanometer. It was launched in 1986 by Nobel Prize winners Gerd Binnig, Calvin Quate and Christoph Gerber.

8 0
3 years ago
What is gravitational acceleration​
Thepotemich [5.8K]

Answer:

gravitational acceleration is the acceleration of an object in free fall within a vacuum (and thus without experiencing drag). This is the steady gain in speed caused exclusively by the force of gravitational attraction.

6 0
3 years ago
Read 2 more answers
Three identical springs, each with stiffness 1200 N/m are attached in series (that is, end to end) to make a longer spring to ho
OLga [1]
<h2>Answer:</h2>

400N/m

<h2>Explanation:</h2>

When n identical springs of stiffness k, are attached in series, the reciprocal of their equivalent stiffness (1 / m) is given by the sum of the reciprocal of their individual stiffnesses. i.e

\frac{1}{m} = ∑ⁿ₁ [\frac{1}{k_{i}}]          -----------------------(i)

That is;

\frac{1}{m} = \frac{1}{k_{1}} + \frac{1}{k_{2}} + \frac{1}{k_{3}} + . . . + \frac{1}{k_{n}}      -------------------(ii)

If they have the same value of stiffness say s, then equation (ii) becomes;

\frac{1}{m} = n x \frac{1}{s}           -----------------(iii)

Where;

n = number of springs

From the question,

There are 3 identical springs, each with stiffness of 1200N/m and they are attached in series. This implies that;

n = 3

s = 1200N/m

Now, to calculate the effective stiffness,m, (i.e the stiffness of a longer spring formed from the series combination of these springs), we substitute these values into equation (iii) above as follows;

\frac{1}{m} = 3 x \frac{1}{1200}

\frac{1}{m} = \frac{3}{1200}

\frac{1}{m} = \frac{1}{400}

Cross multiply;

m = 400N/m  

Therefore, the stiffness of the longer spring is 400N/m

7 0
4 years ago
three neutral metal cans mounted on isulating stands are touching a negatively charge ballon is brought near can a can b is then
Nimfa-mama [501]
Charge on can A is positive. 
Charge on can C is negative.  
Punctuation and capitalization are very useful things to pay attention to and this question would be a lot easier to understand if you had actually used both capitalization and punctuation. If I'm understanding the question, you have 3 metal can that are insulated from the environment and initially touching each other in a straight line. Then a negatively charged balloon is brought near, but not touching one of the cans in that line of cans. While the balloon is near, the middle can is removed. Then you want to know the charge on the can that was nearest the balloon and the charge on the can that was furthermost from the balloon. 
 As the balloon is brought near to can a, the negative charge on the balloon repels some of the electrons from can a (like charges repel). Some of those electrons will flow to can b and in turn flow to can c. Basically you'll have a charge gradient that's most positive on that part of the can that's closest to the balloon, and most negative on the part of the cans that's furthest from the balloon. You then remove can B which causes cans A and C to be electrically isolated from each other and prevents the flow of elections to equalize the charges on cans A and C when the balloon is removed. So you're left with a deficiency of electrons on can A, so can A will have a positive overall charge, and an excess of electrons on can C, so can C will have a negative overall charge.
7 0
3 years ago
How does rolling an object affect its kinetic energy?
ad-work [718]

Answer:

it does happen, search in Google

3 0
3 years ago
Read 2 more answers
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