7. A student is rotating an object on a rope that is 4.5m long. If we increase the length
1 answer:
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Answer:
Acceleration is -30000 mi/h²
Distance travelled in the 3 seconds of deceleration is 261.888 feet
Explanation:
t = Time taken for the car to slow down = 3 s =
u = Initial velocity = 75 mi/h
v = Final velocity = 50 mi/h
s = Displacement
a = Acceleration
Equation of motion
Acceleration is -30000 mi/h²
Converting to feet
1 mile = 5280 feet
0.0496 mile = 0.0496×5280 = 261.888 feet
Distance travelled in the 3 seconds of deceleration is 261.888 feet
If a gun is sighted to hit targets that are at the same height as the gun and 85 m away at the same height, how low, as a positive number in meters, will the bullet hit if aimed directly at a target 180 m away
The muzzle velocity of the bullet is 275 m/s
Answer:
y = -1.1109 m
Explanation:
Range =
range = 85 m
velocity = 275 m/s
g = 9.8 m/s²
If the bullet is aimed at a target 180 m, time required to travel 180 m with horizontal component will be;
t = 0.6546 sec
To determine, how low as a positive number in meters.
y =
y = 0.9909 - 2.1018
y = -1.1109 m