explaining
Algebra
Simplify (2x^2)(4x^3y^2)
(2x2)(4x3y2)(2x2)(4x3y2)
Multiply x2x2 by x3x3 by adding the exponents.
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2x5(4y2)2x5(4y2)
Rewrite using the commutative property of multiplication.
2⋅4(x5y2)2⋅4(x5y2)
Multiply 22 by 44.
8x5y2
We need to identify what "the nearest cent" is.
So!
AB.CD
That is a representation of a number using variables, but we'll just say it's for place values.
A is in the Tens Place
B is in the Ones Place
C is in the Tenths Place (1/10)
D is in the Hundredths Place (1/100
Since we are talking about money let's put it in relation to a dollar.
A is in the Ten Dollar Place
B is in the One Dollar Place
C is in the Tenth of a Dollar Place (1/10 of a dollar)
D is in the Hundredth of a Dollar Place (1/100 of a dollar)
So, what is 1/10 of a dollar?
What amount of money times 10, would get you 1 dollar. Or you can think of it as if you had 10 of one value of money and you got a dollar what is that? A dime.
Now, what is 1/100 of a dollar?
What amount of money times 100, would get you 1 dollar. 1 cent (Or it is sometimes called a penny).
So that means any number beyond the 1/100 of a dollar point (D) will be rounded. If it's the first number after the 1/100 of a dollar is greater than (or equal to) 5 then we round the cent value up. If it is less than 5 we round down.
$29.4983
So, 9 is our cent place. 8 is greater than 5, so we round 9 up. (Add 1. Since it is 9 it will carry over into the 1/10 of a dollar place)
Our answer is:
$29.50
Answer:
C
Step-by-step explanation:
In a Pythagorean triple the square on the longest side is equal to the sum of the squares on the other 2 sides.
A
longest side = 10 ⇒ 10² = 100
6² + 8² = 36 + 64 = 100
A is a Pythagorean triple
B
longest side = 17 ⇒ 17² = 289
8² + 15² = 64 + 225 = 289
B is a Pythagorean triple
C
longest side = 9 ⇒ 9² = 81
5² + 8² = 25 + 64 = 89
89 ≠ 81
C is not a Pythagorean triple
D
longest side = 13 ⇒ 13² = 169
5² + 12² = 25 + 144 = 169
D is a Pythagorean triple
Step-by-step explanation:
Let's represent the number of mochas bought with the variable , and the number of lattes bought with the variable .
Since there are students, the total number of mochas and lattes bought must be . This can be represented with the following equation:
We can also set up another equation based on the total amount spent on the coffe:
If we rearrange the first equation, we can solve for :
If we substitute this into the second equation, we can solve for :
Subtituting this back into the original equation, we can solve for :
Therefore, 9 mochas and 14 lattes were bought.
Answer:
17% i think
Step-by-step explanation: