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3 years ago

6

Yoga Fun charges a $63 starting fee plus $12 per class. Yoga For All charges no starting fee and $15 per class. For how many cla

sses will the cost be the same at both places?
(a) 21
(b) 5
(c) 3
(d) 27

1 answer:

Arada [10]3 years ago

3 0

C) because all are multiple to 3

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Which of the value of x satisfies the equation below -2x-7=12

Masteriza [31]

Answer is A.
You start by adding the 7 to the opposite side. Giving you 19. You divide both sides by -2 which gives you x on one side and -9.5 on the other.

-2x-7=12
-2x=12(+7)
-2x=19
x=19/-2
x=-9.5

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2 years ago

40, 10, 5/2 5/8... (fractions) is it arithmetic or geometric and what are the next two terms PLZ HELP DUE IN 10 MINS

patriot [66]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the sequence

$40,\:10,\:\frac{5}{2},\:\frac{5}{8}$

A geometric sequence has a constant ratio 'r' and is defined by

$\:a_n=a_0\cdot r^{n-1}$

Computing the ratios of all the adjacent terms

$\frac{10}{40}=\frac{1}{4},\:\quad \frac{\frac{5}{2}}{10}=\frac{1}{4},\:\quad \frac{\frac{5}{8}}{\frac{5}{2}}=\frac{1}{4}$

The ratio of all the adjacent terms is the same and equal to

$r=\frac{1}{4}$

Thus, the given sequence is a geometric sequence.

As the first element of the sequence is

$a_1=40$

Therefore, the nth term is calculated as

$\:a_n=a_0\cdot r^{n-1}$

$a_n=40\left(\frac{1}{4}\right)^{n-1}$

Put n = 5 to find the next term

$a_5=40\left(\frac{1}{4}\right)^{5-1}$

$a_5=40\cdot \frac{1}{4^4}$

$a_5=\frac{40}{4^4}$

$=\frac{2^3\cdot \:5}{2^8}$

$a_5=\frac{5}{2^5}$

$a_5=\frac{5}{32}$

now, Put n = 6 to find the 6th term

$a_6=40\left(\frac{1}{4}\right)^{6-1}$

$a_6=40\cdot \frac{1}{4^5}$

$a_6=\frac{40}{4^5}$

$=\frac{2^3\cdot \:5}{2^{10}}$

$a_6=\frac{5}{2^7}$

$a_6=\frac{5}{128}$

Thus, the next two terms of the sequence 40, 10, 5/2, 5/8... is:

$a_5=\frac{5}{32}$

$a_6=\frac{5}{128}$

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3 years ago

A six-foot person walks from the base of a broadcasting tower directly toward the tip of the shadow cast by the tower. When the

mixas84 [53]

B. $\tan{\alpha}= \frac{h}{122+3}$

c.
$\tan{\alpha}=\frac{h}{122+3} = \frac{6}{3}
\\
\\ \frac{h}{125} = 2
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2 years ago

Calculate p² +3q when p=2 and q=2

QveST [7]

Answer:

10

Step-by-step explanation:

p² +3q

= 2² +3*2

=4 + 6

=10

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3 years ago

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Which two numbers are 4 units away from 0 on the number line?

Oduvanchick [21]

Answer: C

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