Question

the perimeter of a rectangle field is 118m. if the length of the rectangle is 7m less than twice the width what is the length​

Answer 1

Let:

P - perimeter

l - length

w - width

We know:

P = 118 m

l = 2w - 7

Rectangle perimeter's formula:   P = 2l + 2w

We replace the length with 2w - 7.

P = 2×(2w - 7) + 2w

118 = 4w - 14 + 2w

118 = 6w - 14

6w = 118 + 14

6w = 132

w = 22 meters

Answer 2

Answer:

w = 22 l = 37

Explanation:

Perimeter = P

Length = l

Width = w

Formula: P = 2 ( w + l ) + 2w

We know

P = 118

l = 2w - 7

Solve

P = 2 (2w - 7) + 2w

118 = 4w - 14 + 2w

118 = 6w - 14

+14          +14

132 = 6w

 6       6

w = 22

2(22) - 7

44 - 7 = 37

l = 37