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3 years ago

the perimeter of a rectangle field is 118m. if the length of the rectangle is 7m less than twice the width what is the length

Mathematics

2 answers:

djyliett [7]3 years ago

8 0

Let:

P - perimeter

l - length

w - width

We know:

P = 118 m

l = 2w - 7

<h3>Rectangle perimeter's formula: P = 2l + 2w</h3>

We replace the length with 2w - 7.

P = 2×(2w - 7) + 2w

118 = 4w - 14 + 2w

118 = 6w - 14

6w = 118 + 14

6w = 132

w = 22 meters

Vitek1552 [10]3 years ago

5 0

Answer:

w = 22 l = 37

Explanation:

Perimeter = P

Length = l

Width = w

Formula: P = 2 ( w + l ) + 2w

We know

P = 118

l = 2w - 7

Solve

P = 2 (2w - 7) + 2w

118 = 4w - 14 + 2w

118 = 6w - 14

6 6

w = 22

2(22) - 7

44 - 7 = 37

l = 37

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3 years ago

the perimeter of a rectangle field is 118m. if the length of the rectangle is 7m less than twice the width what is the length​

the perimeter of a rectangle field is 118m. if the length of the rectangle is 7m less than twice the width what is the length