the perimeter of a rectangle field is 118m. if the length of the rectangle is 7m less than twice the width what is the length
2 answers:
Let:
P - perimeter
l - length
w - width
We know:
P = 118 m
l = 2w - 7
<h3>Rectangle perimeter's formula: P = 2l + 2w</h3>
We replace the length with 2w - 7.
P = 2×(2w - 7) + 2w
118 = 4w - 14 + 2w
118 = 6w - 14
6w = 118 + 14
6w = 132
w = 22 meters
Answer:
w = 22 l = 37
Explanation:
Perimeter = P
Length = l
Width = w
Formula: P = 2 ( w + l ) + 2w
We know
P = 118
l = 2w - 7
Solve
P = 2 (2w - 7) + 2w
118 = 4w - 14 + 2w
118 = 6w - 14
<u>+14 +14</u>
<u>132</u> = <u>6w</u>
6 6
w = 22
2(22) - 7
44 - 7 = 37
l = 37
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