A brick is dropped from a big scaffold. What is its velocity after 4.0s?
1 answer:
The velocity of the brick is 39.2 m/s downward
Explanation:
The motion of the brick is a free fall motion, since the object is affected only by the force of gravity. Therefore, it has a uniformly accelerated motion towards the ground, with constant acceleration of .
So, we can find its velocity using the suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the brick in this problem (taking downward as positive direction)
u = 0 (it is dropped from rest)
Therefore, its velocity after t = 4.0 s is:
Downward, because the sign is positive.
Learn more about free fall motion:
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Answer:
The answer is: The increased voltage causes an increase in power usage, and the device will over-heat.
Explanation:
First, we must consider the variables of the electrical system that will allow us to respond. In this case, power, current and voltage, which are related by
Where P=Power, V=Voltage, I=Current.
In the equation it can be observed that power is directly proportional to the system voltage. Thus, if the voltage increases as in this case, the power will also increase, which overheats the device and can cause damage to it.