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mr Goodwill [35]
3 years ago
6

A rocket of mass 1200kg is travelling at 2000m/s .It fires its engine for 1 min .The forwarded thrust provided by the rocket eng

ines is 10KN (10000 N) .
a)Use the equation of momentum x t to calculate the increase in the momentum of the rocket .
b)use your answer a to calculate the increase in velocity of the rocket and its new velocity after firing the engines .
Physics
1 answer:
hodyreva [135]3 years ago
5 0

Answer:it fires its engine for 1 minute. If the forward thrust provided by the rocket engines is 10000 N, what is the increase in ... From this, work out the increase in velocity of the rocket and its new velocity ... You can put this solution on YOUR website! . From Physics (Mechanics), there is this impulse-momentum change equation: ...

Explanation:

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3 0
3 years ago
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Would a plant placed in an atmosphere of pure oxygen be able to conduct Photosynthesis
aalyn [17]
NO , because plants require carbon dioxide to preform photosynthesis.
4 0
3 years ago
The ratio of the inductive reactance to the
BARSIC [14]

Answer:

<em>The non resonance frequency of the generator is = 1201.79 Hz</em>

Explanation:

At resonance,

f₀ = 1/2π√LC..................... Equation 1

Where f₀ = resonance frequency, L = inductance, C = capacitance

making LC the subject of the equation

LC = 1/4πf₀²..................... Equation 2

<em>Given: </em>f₀ = 225 Hz, and π = 3.143

<em>Substituting these values into equation 2,</em>

LC = 1/(4×3.143²×225²)

LC = 1/2000385.9

LC = 5×10⁻⁷

If the ratio of capacitive reactance to inductive reactance = 5.36

1/2πfC/2πfL = 5.36

1/4π²f²LC = 5.36

Where f = frequency of the non resonant

making f the subject of the equation

f = 5.36/2π√LC ............. Equation 3

Substituting the value of LC = 5×10⁻⁷ into equation 3

f = 5.36/2×3.143√(5×10⁻⁷)

f = 5.36/(6.286×0.00071)

f = 5.36/0.00446

<em>f = 1201.79 Hz</em>

<em>Thus the non resonant frequency of the generator is = 1201.79 Hz</em>

6 0
2 years ago
The free body diagram represents Silly Sally hanging from a trapeze bar. Sally weighs 660 Newtons. What is the force in each of
Y_Kistochka [10]
A) 330 N

Explanation: Her weight must be evenly distributed between the chains (assuming they are at an even level), so you divide 660 by 2 and get 330
7 0
3 years ago
Chapter 16, Problem 63. A person is standing in a room at 18 ◦C. The exposed surface area and skin temperature of the person are
Juliette [100K]

Answer:Q=248.011 W

Explanation:

Given

Temperature of Room T_{\infty }=18^{\circ}\approx 291 K

Area of Person A=1.7 m^2

Temperature of skin T=32^{\circ}\approx 305 K

Heat transfer coefficient h=5 W/m^2.k

Emissivity of the skin and clothes \epsilon =0.9

\Delta T=32-18=14^{\circ}

Total rate of heat transfer=heat Transfer due to Radiation +heat transfer through convection

Heat transfer due radiation Q_1=\epsilon \sigma A(T^4-T_{\infty }^4 )

where \sigma =stefan-boltzman\ constant

Q_1=0.9\times 5.687\times 10^{-8}\times 1.7\times (305^4-291^4)

Q_1=129.01 W

Heat Transfer due to convection is given by

Q_2=hA(\Delta T)

Q_2=5\times 1.7\times 14=119 W

Q=Q_1+Q_2

Q=129.01+119=248.011 W

7 0
3 years ago
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