A rocket of mass 1200kg is travelling at 2000m/s .It fires its engine for 1 min .The forwarded thrust provided by the rocket eng
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Answer:
here we can say that acceleration of the satellite is same as the gravitational field due to Earth at that location
Explanation:
As we know that gravitational field is defined as the force experienced by the satellite per unit of mass
so we will have
now in order to find the acceleration of the satellite we know by Newton's II law
so we will have
so here we can say that acceleration of the satellite is same as the gravitational field due to Earth at that location
According to the law of conservation of momentum:
m1 = mass of first object
m2 = mass of second object
v1 = Velocity of the first object before the collision
v2 = Velocity of the second object before the collision
v'1 = Velocity of the first object after the collision
v'2 = Velocity of the second object after the collision
Now how do you solve for the velocity of the second car after the collision? First thing you do is get your given and fill in what you know in the equation and solve for what you do not know.
m1 = 125 kg v1 = 12m/s v'1 = -12.5m/s
m2 = 235kg v2 = -13m/s v'2 = ?
Transpose everything on the side of the unknown to isolate the unknown. Do not forget to do the opposite operation.
The velocity of the 2nd car after the collision is 0.03m/s.
m1 = mass of first object
m2 = mass of second object
v1 = Velocity of the first object before the collision
v2 = Velocity of the second object before the collision
v'1 = Velocity of the first object after the collision
v'2 = Velocity of the second object after the collision
Now how do you solve for the velocity of the second car after the collision? First thing you do is get your given and fill in what you know in the equation and solve for what you do not know.
m1 = 125 kg v1 = 12m/s v'1 = -12.5m/s
m2 = 235kg v2 = -13m/s v'2 = ?
Transpose everything on the side of the unknown to isolate the unknown. Do not forget to do the opposite operation.
The velocity of the 2nd car after the collision is 0.03m/s.