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topjm [15]
3 years ago
5

What is the speed of a sound wave that takes 0.5 s to travel 750 m?

Physics
1 answer:
kvasek [131]3 years ago
4 0

Answer:

C. 1500.

Explanation:

750 / .5 = 1500.

Hope this helps & best of luck!

Feel free to message me if you need more help! :)

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Are you for or against using nuclear energy?
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Answer:

Against but it really depends on the situation

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Two identical wind-up cars A and B are released. Car B has a 2 kilogram weight strapped to the back of the car. Which will have
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Car A would have a better average speed

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added weight to a object that is self propelled will be slower than a identical object with no added weight

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How do you determine the wattage capacity needed by a power supply?
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P = V²/R or P = V * I

Hope this helps!
6 0
2 years ago
The record time for a Tour de France cyclist to ascend the 1100-m-high Alpe d'Huez is 37.5 min. The rider and his bike had a mas
Leni [432]

Answer

given,

height of Alpe d'Huez =  1100-m

time = 37.5 min

mass of the rider and his bike = 65 Kg

the metabolic power to ride = 700 W

U = m g y

U = 65 x 9.8 x 1100

U = 700700 J

since efficiency is 25%

E_{chem} = \dfrac{U}{e}

E_{chem} = \dfrac{700700}{0.25}

E_{chem} = 2802800

E_{chem} = \dfrac{2802800}{4.19 \time 10^3}

E_{chem} =668.9\ cal

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8 0
3 years ago
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Two identical conducting spheres are placed 80.0 cm apart. One is given a charge of 5.8 C and the other is given a charge of 6.4
Zepler [3.9K]

Answer: 5.214(10)^{11} N

Explanation:

According to <u>Coulomb's Law:</u>  

<em>"The electrostatic force F_{E} between two point charges q_{1} and q_{2} is proportional to the product of the charges and inversely proportional to the square of the distance d that separates them, and has the direction of the line that joins them".</em>

<em />

Mathematically this law is written as:

F_{E}=K\frac{q_{1}.q_{2}}{d^{2}}  

Where:

F_{E}  is the electrostatic force

K=8.99(10)^{9} Nm^{2}/C^{2} is the Coulomb's constant  

q_{1}=5.8 C and q_{2}=6.4 C are the electric charges

d=80 cm \frac{1 m}{100 cm}=0.8 m is the separation distance between the charges

Solving:

F_{E}=8.99(10)^{9} Nm^{2}/C^{2}\frac{(5.8 C)(6.4 C)}{(0.8 m)^{2}}  

F_{E}=5.214(10)^{11} N    

7 0
3 years ago
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