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Ber [7]
3 years ago
11

Q: What happens when cold air approaches a body of warm air?     Optional Answers:      A. The Warm air rises.     B. The warm a

nd cold air both disappear.      C. The warm and cold air mix immediately.     D. The cold air rises. 
Physics
2 answers:
artcher [175]3 years ago
8 0
A. The warm air rises! Hope this helps
Dafna11 [192]3 years ago
8 0
Answer a is correct.
Warm air rises.
EXAMPLE: when your cooking the hot air or warm air rises or moves upward.
Hope I helped.
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An astronaut on Pluto attaches a small brass ball to a 1.00-m length of string and makes a simple pendulum. She times 10 complet
pickupchik [31]

Answer:

The acceleration due to gravity at Pluto is 0.0597 m/s^2.

Explanation:

Length, L = 1 m

10 oscillations in 257 seconds

Time period, T = 257/10 = 25.7 s

Let the acceleration due to gravity is g.

Use the formula of time period of simple pendulum

T = 2\pi\sqrt{\frac{L}{g}}\\\\25.7 = 2 \times 31.4\sqrt{\frac{1}{g}}\\\\g = 0.0597 m/s^2

7 0
3 years ago
Solve the problem.
gulaghasi [49]
As the shock waves travel in concentric outward circles from the epicenter, and the diameter is measured 120 miles,
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d=120
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3 years ago
A constant power is supplied to a rotating disc .the relationship of angular velocity of disc and number of rotations made by th
Bogdan [553]
A rotating disc supplied with constant power where the relationship of the angular velocity of the disc and the number of rotations made by the disc is governed by Newton's second law for rotation. This law is specially made for rotating bodies which is extracted from Newton's second law of motion. 
6 0
3 years ago
The distance between stars is typically measured in
Murljashka [212]
<span>The question says: complete the sentence: The distance between stars is typically measured in.... The answer is 'light years" - the distance that light travels in a year. That's because it's a very big unit and if we were using smaller units, we would be using huge numbers that would be hard to read and would take up a lot of space.</span>
3 0
3 years ago
When water is boiled under a pressure of 2.00atm, the heat of vaporization is 2.20×106J/kg and the boiling point is 120∘C. At th
Vikki [24]

Answer:

2033219.05 J

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V = Volume

P = Pressure = 2 atm

m = Mass of water = 1 kg

L_v = Heat of vaporization = 2.2\times 10^6\ J/kg

Work done in an isobaric system is given by

W=-P\Delta V\\\Rightarrow W=-2\times 101325\times (1\times 10^{-3}-0.824)\\\Rightarrow W=166780.95\ J

Work done is 166780.95 J

Change in internal energy is given by

\Delta U=Q-W

Heat is given by

Q=mL_v\\\Rightarrow Q=1\times 2.2\times 10^6\\\Rightarrow Q=2.2\times 10^6\ J

\Delta U=2.2\times 10^6-166780.95\\\Rightarrow \Delta U=2033219.05\ J

The increase in internal energy of the water is 2033219.05 J

6 0
3 years ago
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