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3 years ago

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The distance between stars is typically measured in

1 answer:

Murljashka [212]3 years ago

3 0

<span>The question says: complete the sentence: The distance between stars is typically measured in.... The answer is 'light years" - the distance that light travels in a year. That's because it's a very big unit and if we were using smaller units, we would be using huge numbers that would be hard to read and would take up a lot of space.</span>

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A filing cabinet weighing 556 N rests on the floor. The coefficient of static friction between it and the floor is 0.68, and the

zvonat [6]

Explanation:

"Static friction is a force that keeps an object at rest. It must be overcome to start moving the object."

(556 x 0.68) = static friction of 378.08N. before movement occurs.

The forces (a) and (b) will not move it.

Each will incur a frictional force preventing movement equal to itself, = 222N. and 334N. respectively.

Forces (c) and (d) will move it, and accelerate it.

Forces (c) and (d) will both encounter friction of (556 x 0.56) = 311.36N. when the cabinet is moving.

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3 years ago

______ is an environmental group that works to create awareness of pollution

Cerrena [4.2K]

B) Greenpeace

Why? They work to create awareness (:

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2 years ago

A heat engine is a device that uses _____to produce useful work.

MakcuM [25]

A heat engine is a device that uses heat to produce useful work.

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3 years ago

Read 2 more answers

Explain relative velocity briefly

fomenos

Answer:

Explanation:

Relative velocity is defined as the velocity of an object B in the rest frame of another object A.

4 0

3 years ago

Alan leaves Los Angeles at 8:00 a.m. to drive to San Francisco, 400 mi away. He travels at a steady 45.0 mph . Beth leaves Los A

WARRIOR [948]

Answer:

a.Beth

b.2232 s

Explanation:

We are given that

Distance,d=400 mi

Speed of Alan,v=45 mph

Speed of Beth,v'=55 mph

a.Time = $\frac{distance}{speed}$

Using the formula

Time taken by Alan= $\frac{400}{45}=8.89 hr$

Time taken by Beth= $\frac{400}{55}=7.27hr$

Alan will reach San Francisco at 4:53 PM

Beth will reach San Francisco at 4:16 PM

Beth will reach before Alan.

b.Difference between time=8.89-7.27=1.62 hr

t=1.62 hr

1.62-1=0.62 hr

0.62 hr= $0.62\times 60\times 60=2232 s$

Hence, Beth has to wait 2232 s for Alan to arrive .

6 0

3 years ago