Answer: The spring potential energy must equal or exceed the energy to raise the mass to loop height and the minimum kinetic energy needed to keep the mass in contact with the top of the loop
kd² = 5Mrg
h = kd²/2Mg
Explanation:
at top of loop
Mv²/r = Mg
v² = rg
½kd² = ½Mv² + Mgh'
½kd² = ½M(rg) + Mg(2r)
½kd² = 2.5Mrg
kd² = 5Mrg
½kd² = Mgh
h = kd²/2Mg
Answer:
compressions; rarefactions
Explanation:
Answer:
The pressure on the wall is 9416.25 N/m²
Explanation:
Please see the attachments below
Well it would tell us the number of neutrons and protons in the nucleus so i would assume the number of energy levels.
mass of the box = 20 kg
force of friction on the box due to surface



similarly kinetic friction on it



now the weight of the suspended block will be

so here the weight of the suspended block is less than the limiting friction on it
So here we will say that friction will counter balance the weight of the suspended block and it will not move at all
So acceleration of the box will be zero