Answer:
Steel
Explanation:
Mass is density times volume.
m = ρV
Since they have the same size and shape, they have the same volume.
Steel has a higher density than Styrofoam, so at the same volume, the steel ball will have more mass.
Answer:
Explanation:
A combination of two controlled variables will make an experiment the most reliable.
Variables are the values that we take under any circumstance while doing an experiment so that we can keep on changing and get new results at the end.
It is important to have them in pair so that two values can be kept on changing in terms of any constant condition. This will help to get better results in over all experiment data.
Velocity of submarine A is vs = 11.0m/s
frequency emitted by submarine A. F = 55.273 × 10∧3HZ
Velocity of submarine B = vO = 3.00m/s
The given equation is
f' = ((V + vO) ((v - vS)) × f
The observer on submarine detects the frequency f'.
The sign of vO should be positive as the observer of submarine B is moving away from the source of submarine A.
The speed of the sound used in seawater is 1533m/s
The frequency which is detected by submarine B is
fo = fs (V -vO/ v +vs)
= 53.273 × 10∧3hz) ((1533 m/s - 4.5 m/s)/ (1533 m/s +11 m/s)
fo = 5408 HZ
While pushing a refrigerator up a ramp, there would be less friction to overcome if you used a dolly because of the wheels. So the efficiency of the ramp would be greater with the use of the dolly.
<u>Explanation:</u>
The ramp provides for a wedge setup, so when the refrigerator is being pushed up the ramp, the friction on the ramp would equally distributed to the refrigerator when pushed wholly as the friction applied is a product of the coefficient of friction with the Normal reaction of the weight in contact with the surface.
Therefore, when the dolly is used, the surface in contact becomes divided and thus, the friction applied would become less due to though coefficient of friction remains the same, the normal reaction of the weight becomes small and so does the applied friction. Therefore, efficiency of the ramp increases as the friction is less and work done is more.
Answer:
0.369 V
<u>Explanation:</u>
Given :
Capacitance ( c ) = 650 × 10–4 F
Charge ( q ) = 24 × 10–3 C
We are asked to find potential difference ( v )!
We know:
q = c v
= > v = q / c
Putting values here we get:
= > v = ( 24 × 10–3 ) / ( 650 × 10–4 ) V
= > v = 240 / 650 V
= > v = 24 / 65 V
= > v = 0.369 V
Therefore, potential difference between the plates is 0.369 V
