A rugby player of mass 75 kg, running east at 8.0 m/s, tackles another player of mass 90 kg who is running directly towards him at 5.0 m/s. If the two players cling together after the tackle, what will be their common velocity?
1 answer:
You can use the formula:(m1 + m2)vf = m1vi m1 = mass of first rugby player (75 kg) m2 = mass of second rugby player (90) vf = their final velocity vi = the initial velocity (m1 + m2)vf = m1vi (75 + 90)vf = (75)(8.0) 165(vf) = 600 vf = 3.64 m/s hope this helps :)
You might be interested in
The answer is Prove a hypothesis
Answer: For what objects? And what data?
Explanation:
<span>b) units and numbers</span>
D The parent material refers the the rock that was responsible for the formation of a certain soil.
Answer:
pressure = force/area
force = 200N
area = πr², π =3.142, r = 12 cm = 0.12 m
pressure = 200/3.142×(0.12)²
p = 200/3.142×0.24
p = 200/0.754
p = 265.25 Nm-¹ or 265.25 Pa