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koban [17]
3 years ago
13

After a big snowfall, you take your favorite rocket‑powered sled out to a wide field. The field is 223 m223 m across, and you kn

ow that your sled accelerates at a rate of 3.25 m/s23.25 m/s2 when the rocket is on. How much time will it take the sled to cross the field starting from rest, assuming the rocket is on the whole time?
Physics
1 answer:
pogonyaev3 years ago
6 0

Answer:

11.7 s

Explanation:

In this problem, the rocket is moving in a uniform accelerated motion. We have the following data:

d = 223 m, the distance that the sled has to cover

a=3.25 m/s^2, the acceleration of the rocket

We can use therefore the following SUVAT equation:

d=ut+\frac{1}{2}at^2

where

d is the distance

u = 0 is the initial velocity of the sled (it starts from rest)

t is the time

a is the acceleration

Re-arranging the equation and substituting the numbers, we find the time it takes for the rocket to cross the field:

d=\frac{1}{2}at^2\\t=\sqrt{\frac{2d}{a}}=\sqrt{\frac{2(223)}{3.25}}=11.7 s

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Answer:

v = r\omega

Explanation:

If the object is rolling without slipping, every unit of rotated angle equals to a distance perimeter rotated.

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3 years ago
Calculate the molarity of a 10. 0% cacl₂ solution. The density of the solution is 1. 0835 g/cm³.
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The molarity of 10% CaCl2 is 0.9%

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