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koban [17]
3 years ago
13

After a big snowfall, you take your favorite rocket‑powered sled out to a wide field. The field is 223 m223 m across, and you kn

ow that your sled accelerates at a rate of 3.25 m/s23.25 m/s2 when the rocket is on. How much time will it take the sled to cross the field starting from rest, assuming the rocket is on the whole time?
Physics
1 answer:
pogonyaev3 years ago
6 0

Answer:

11.7 s

Explanation:

In this problem, the rocket is moving in a uniform accelerated motion. We have the following data:

d = 223 m, the distance that the sled has to cover

a=3.25 m/s^2, the acceleration of the rocket

We can use therefore the following SUVAT equation:

d=ut+\frac{1}{2}at^2

where

d is the distance

u = 0 is the initial velocity of the sled (it starts from rest)

t is the time

a is the acceleration

Re-arranging the equation and substituting the numbers, we find the time it takes for the rocket to cross the field:

d=\frac{1}{2}at^2\\t=\sqrt{\frac{2d}{a}}=\sqrt{\frac{2(223)}{3.25}}=11.7 s

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Base on my research, as of 2004 The U.S. devours about 20 million barrels of oil a day, according to the CIA. But base on Wikipedia, it says that a normal large tanker can only carry around 2 million barrels of oil. So to supply the U.S with this oil per day, it needs 10 normal large oil tankers. 
8 0
3 years ago
What ocean depth would the volume of an aluminium sphere be reduced by 0.10%
yKpoI14uk [10]

Answer:

6400 m

Explanation:

You need to use the bulk modulus, K:

K = ρ dP/dρ

where ρ is density and P is pressure

Since ρ is changing by very little, we can say:

K ≈ ρ ΔP/Δρ

Therefore, solving for ΔP:

ΔP = K Δρ / ρ

We can calculate K from Young's modulus (E) and Poisson's ratio (ν):

K = E / (3 (1 - 2ν))

Substituting:

ΔP = E / (3 (1 - 2ν)) (Δρ / ρ)

Before compression:

ρ = m / V

After compression:

ρ+Δρ = m / (V - 0.001 V)

ρ+Δρ = m / (0.999 V)

ρ+Δρ = ρ / 0.999

1 + (Δρ/ρ) = 1 / 0.999

Δρ/ρ = (1 / 0.999) - 1

Δρ/ρ = 0.001 / 0.999

Given:

E = 69 GPa = 69×10⁹ Pa

ν = 0.32

ΔP = 69×10⁹ Pa / (3 (1 - 2×0.32)) (0.001/0.999)

ΔP = 64.0×10⁶ Pa

If we assume seawater density is constant at 1027 kg/m³, then:

ρgh = P

(1027 kg/m³) (9.81 m/s²) h = 64.0×10⁶ Pa

h = 6350 m

Rounded to two sig-figs, the ocean depth at which the sphere's volume is reduced by 0.10% is approximately 6400 m.

6 0
3 years ago
How fast is the sixth cosmic velocity?
denpristay [2]
<span>25,000 miles per hour

hope that this helps</span>
3 0
3 years ago
Give at least one fact about subatomic particles
victus00 [196]

Answer:

- Particles smaller than atoms are called subatomic particles .

- There are three famous subatomic particles, proton, neutron and electron .

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6 0
3 years ago
A closely wound rectangular coil of 80 turns has dimensions 25.0 \rm cm by 40.0 \rm cm. The plane of the coil is rotated from a
Pepsi [2]

Answer:

88.3

Explanation:

Emf in a rotating coil is given by rate of change of flux:

E= dФ/dt=(NABcos∅)/ dt

N: number of turns in the coil= 80

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B: magnetic field strength= 1.1

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4 0
3 years ago
Read 2 more answers
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