What is the value of x. x-3/7=4
1 answer:
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Answer:
The equation of line with given points is y - 4 = 3 ( x + 2 ) .
Step-by-step explanation:
Given as :
The points of line are ( 1 , 13 ) and ( - 2 , 4 )
The point slope intercept equation of line is
y - = m ( x -
)
Where m is the slope of line
So , Slope , m =
Or, m =
Or, m =
∴ m = 3
Now The equation of line is
y - = m ( x -
)
Or. y - 13 = 3 ( x - 1 )
Or, y - 13 = 3 x - 3
Or, y = 3 x - 3 + 13
∴ y = 3 x + 10
I.e y - 4 = 3 x + 6
Or, y - 4 = 3 ( x + 2 )
Hence The equation of line with given points is y - 4 = 3 ( x + 2 ) . Answer
Answer:
x ≈ 7.2
Step-by-step explanation:
Given a tangent- secant from an external point to the circle, then
the the square of the measure of the tangent is equal to the product of the external part of the secant and the entire secant, that is
x² = 4(4 + 9) = 4 × 13 = 52 ( take the square root of both sides )
x = ≈ 7.2 ( to the nearest tenth )
