I think it is C. but Im not positive
Answer:
The volume of the sphere is ![V=18\pi\ ft^{3}](https://tex.z-dn.net/?f=V%3D18%5Cpi%5C%20ft%5E%7B3%7D)
Step-by-step explanation:
we know that
The volume of cylinder is equal to
![V=\pi r^{2}h](https://tex.z-dn.net/?f=V%3D%5Cpi%20r%5E%7B2%7Dh)
we have
![V=27\pi\ ft^{3}](https://tex.z-dn.net/?f=V%3D27%5Cpi%5C%20ft%5E%7B3%7D)
substitute
![27\pi=\pi r^{2}h](https://tex.z-dn.net/?f=27%5Cpi%3D%5Cpi%20r%5E%7B2%7Dh)
simplify
Remember that
A sphere and a cylinder have the same radius and height
so
The height of cylinder is equal to the diameter of sphere
h=2r
substitute
-----> equation A
The volume of the sphere is equal to
![V=\frac{4}{3}\pi r^{3}](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E%7B3%7D)
substitute equation A in the formula of the volume of sphere
![V=\frac{4}{3}\pi (13.5)](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%2813.5%29)
![V=18\pi\ ft^{3}](https://tex.z-dn.net/?f=V%3D18%5Cpi%5C%20ft%5E%7B3%7D)
Answer: I believe the answer is C.
Step-by-step explanation: In special case isosceles right triangles the hypotenuse is always equal to a · √2. With a=5√2 we can set up the equation 5√2 · √2 = 10.
Answer:
D
Step-by-step explanation:
∠ABC= ∠DBE (vert. opp. ∠s)
(6x -7)°= (4x +23)°
6x -7= 4x +23
<em>Being</em><em> </em><em>x</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>,</em><em> </em><em>constant</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em>:</em>
6x -4x= 23 +7
<em>Simplify</em><em>:</em>
2x= 30
<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>2</em><em>:</em>
x= 15
<em>Substituting</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>x</em><em>:</em>
m∠ABC
= 6(15) -7
= 83
Answer:
a. 2.5..... I believe but you should get other answers