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worty [1.4K]
4 years ago
9

A 2.3 kg object has 15 ) of kinetic energy. Calculate its speed.

Chemistry
1 answer:
chubhunter [2.5K]4 years ago
7 0

Answer:

<h3>The answer is option D</h3>

Explanation:

To find the speed given the kinetic energy and mass we use the formula

v =  \sqrt{ \frac{2KE}{m} }  \\

where

m is the mass

v is the speed

From the question

KE = 15 J

m = 2.3 kg

We have

v =  \sqrt{ \frac{2 \times 15}{2.3} }  =  \sqrt{ \frac{30}{2.3} }  \\  = 3.61157559...

We have the final answer as

<h3>3.6 m/s</h3>

Hope this helps you

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Answer: 40.3 L

Explanation:

To calculate the moles :

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\text{Moles of} Sb_2O_3=\frac{175g}{291.5g/mol}=0.600moles

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According to stoichiometry :

1 moles of Sb_2O_3 produces = 3 moles of CO

Thus 0.600 moles of Sb_2O_3 will produce=\frac{3}{1}\times 0.600=1.80moles  of CO

Volume of CO=moles\times {\text {Molar volume}}=1.80moles\times 22.4L/mol=40.3L

Thus 40.3 L of CO is produced.

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3 years ago
Annie learns that the compound sulfuric acid is called the universal chemical. The acid is used in everything from gasoline to p
pochemuha

Answer:

D. H2SO4

Explanation:

The chemical  formula of a compound is an expression that stares out the elements (in form of symbols)present in a compound and the number of the atoms.

In the image;

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Which electron configuration represents a violation of the pauli exclusion principle?
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To a 25.00 mL volumetric flask, a lab technician adds a 0.150 g sample of a weak monoprotic acid, HA , and dilutes to the mark w
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<u>Answer:</u> The number of moles of weak acid is 4.24\times 10^{-3} moles.

<u>Explanation:</u>

To calculate the moles of KOH, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}\text{Volume of solution (in L)}}

We are given:

Volume of solution = 43.81 mL = 0.04381 L      (Conversion factor: 1L = 1000 mL)

Molarity of the solution = 0.0969 moles/ L

Putting values in above equation, we get:

0.0969mol/L=\frac{\text{Moles of KOH}}{0.04381}\\\\\text{Moles of KOH}=4.24\times 10^{-3}mol

The chemical reaction of weak monoprotic acid and KOH follows the equation:

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By Stoichiometry of the reaction:

1 mole of KOH reacts with 1 mole of weak monoprotic acid.

So, 4.24\times 10^{-3}mol of KOH will react with = \frac{1}{1}\times 4.24\times 10^{-3}=4.24\times 10^{-3}mol of weak monoprotic acid.

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3 years ago
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