Answer:
I think it's A because the sedimentary rock is also involved in finding the fossils to determine their phenotype and their roots.
The order of reaction with respect to a is 4 and with respect to b is 5 for a reaction that obeys the rate law.
The order of reaction is equal sum of power of concentration of the each reactant present in the reaction that obeys the rate law . The order of individual reactant or species present in the rate law is equal to the power of the of concentration of the respective species or reactant .
Example : If rate law is given as,
rate = k![[a]^{4} [b]^{5}](https://tex.z-dn.net/?f=%5Ba%5D%5E%7B4%7D%20%5Bb%5D%5E%7B5%7D)
The order of reaction with respect to a is 4 and with respect to b is 5 for a reaction that obeys the rate law.
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Answer:
B) an anion
Explanation:
During bonding atoms may share electron or give out electron . In the case of electrovalent or ionic bonding, electron(s) is/are transferred from one atom to another . The atom that donate the electron are known as donor atom and the atom that receives the electron are known as receivers.
The atom that donate the electron becomes a cation(positively charged) as it lose it electron(s) while the receiver gains electron to become an anion which is a negatively charge ion.
An example of such interaction is between a sodium atom and a chlorine atom. The Na atom lose it electron to become positively charged(cation) while the chlorine atom gains electron to become negatively charged(anion). Both atom bond together losing and gaining electron to fulfill the octet rule.
Na+ + Cl- → NaCl
2Al + 3ZnCl₂ ----> 3Zn + 2AlCl₃
What is the coefficient in front of AlCl₃? ==>> 2
Answer:
Percent by mass of water is 56%
Explanation:
First of all calculate the mass of hydrated compound as,
Mass of Sodium = Na × 2 = 22.99 × 1 = 45.98 g
Mass of Sulfur = S × 1 = 32.06 × 1 = 32.06 g
Mass of Oxygen = O × 14 = 16 × 14 = 224 g
Mass of Hydrogen = H × 20 = 1.01 × 20 = 20.2 g
Mass of Na₂S0₄.10H₂O = 322.24 g
Secondly, calculate mass of water present in hydrated compound. For this one should look for the coefficient present before H₂O in molecular formula of hydrated compound. In this case the coefficient is 10, so the mass of water is...
Mass of water = 10 × 18.02
Mass of water = 180.2 g
Now, we will apply following formula to find percent of water in hydrated compound,
%H₂O = Mass of H₂O / Mass of Hydrated Compound × 100
Putting values,
%H₂O = 180.2 g / 322.24 g × 100
%H₂O = 55.92 % ≈ 56%
