The empirical formula of metal iodide : CoI₃(Cobalt(III) Iodide)
<h3>Further explanation</h3>
13.02 g sample of Cobalt , then mol Co(MW=58.933 g/mol) :

Mass of metal iodide formed : 97.12 g, so mass of Iodine :

Then mol iodine (MW=126.9045 g/mol) :

mol ratio of Cobalt and Iodine in the compound :
Answer:
NH4)3PO4
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Answer:
First choice: 2
Explanation:
There are 2 phosphorous (P) in the substance.
Ignore the strontium (Sr3) part because you are looking to isolate the P from (PO4)2.
Break the chemical equation apart to get 1 Phosphorous atom, and 4 Oxygen atoms.
Now, multiple 1 by 2 because that are 2 phosphate to get 2 phosphorous atoms.
Answer: by boiling the water to have it evaporate in to water vaper
Explanation: