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aivan3 [116]
2 years ago
15

What is the order of reaction with respect to a and b for a reaction that obeys the rate law: rate = k[a]4[b]5?

Chemistry
1 answer:
spin [16.1K]2 years ago
3 0

The order of reaction with respect to a is 4 and with respect to b is 5 for a reaction that obeys the rate law.

The order of reaction is equal sum of power of concentration of the each reactant present in the reaction  that obeys the rate law . The order of individual reactant or species present in the rate law is equal to the power of the of concentration of the respective species or reactant .

Example : If rate law is given as,

rate = k[a]^{4} [b]^{5}

The order of reaction with respect to a is 4 and with respect to b is 5 for a reaction that obeys the rate law.

To learn more about order of reaction please click here

brainly.com/question/1769080

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Grignard reactions are highly exothermic and are performed in ether solvent. There is a real risk of fire during this reaction.
AleksAgata [21]

Answer:

Ideally, extinguish the flames with a glass watch or beaker.

Explanation:

When you cover the distillation equipment with a watch glass or beaker, you reduce the oxygen content and it is completely eliminated thanks to the fire itself that consumes it. Once there is no more oxygen the fire is extinguished and it should take no more than 2 or 3 seconds to occur this situation

It is the easiest and most careful way to extinguish the fire during the Grignard reaction

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3 years ago
Green (Gg) Is crossed with a yellow pea plant (Gg )
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What happens to an object as its thermal energy increases?
aleksandr82 [10.1K]

Answer:

It heats up

Explanation:

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3 years ago
A balloon of helium gas in Alabama has a volume of 22.4 L at 26°C and a 1.03 ATM how big with a balloon get if is transported to
Dimas [21]

Answer:

The final volume of the balloon is = 28.11 L

Explanation:

Initial pressure P_{1} = 1.03 atm = 104.325 K pa

Initial temperature T_{1} = 26 °c = 299 K

Initial volume V_{1} = 22.4 L

Final temperature T_{2} = 22 °c = 295 K  

Final pressure P_{2} = 0.81 atm = 82 K pa

We know that

\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }

Put all the values in above formula we get

\frac{(104.325)(22.4)}{299} = \frac{(82)(V_{2} )}{295}

V_{2} = 28.11 L

This is the final volume of the balloon.

8 0
3 years ago
The following reaction produces ethanoic acid (CHACOOH) from methanol (CH3OH) and carbon
tigry1 [53]

Answer:

\boxed{\text{300 g}}

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r:         32                          60

           CH₃OH + CO ⟶ CH₃COOH

m/g:        160

(a) Moles of CH₃OH

\text{Moles of CH$_{3}$OH} = \text{160 g CH$_{3}$OH }\times \dfrac{\text{1 mol CH$_{3}$OH }}{\text{32 g CH$_{3}$OH}}= \text{5.00 mol CH$_{3}$OH}

(b) Moles of CH₃COOH

\text{Moles of CH$_{3}$COOH} = \text{5.00 mol CH$_{3}$OH } \times \dfrac{\text{1 mol CH$_{3}$COOH}}{\text{1 mol CH$_{3}$OH }} = \text{5.00 mol CH$_{3}$COOH}

(c) Mass of CH₃COOH

\text{Mass of CH$_{3}$COOH} =\text{5.00 mol CH$_{3}$COOH} \times \dfrac{\text{60 g CH$_{3}$COOH}}{\text{1 mol CH$_{3}$COOH}} = \textbf{300 g CH$_{3}$COOH}\\\\\text{The maximum mass of ethanoic acid that can be produced is $\boxed{\textbf{300 g}}$}

3 0
4 years ago
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