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2 years ago

What is the order of reaction with respect to a and b for a reaction that obeys the rate law: rate = k[a]4[b]5?

Chemistry

1 answer:

spin [16.1K]2 years ago

3 0

The order of reaction with respect to a is 4 and with respect to b is 5 for a reaction that obeys the rate law.

The order of reaction is equal sum of power of concentration of the each reactant present in the reaction that obeys the rate law . The order of individual reactant or species present in the rate law is equal to the power of the of concentration of the respective species or reactant .

Example : If rate law is given as,

rate = k $[a]^{4} [b]^{5}$

The order of reaction with respect to a is 4 and with respect to b is 5 for a reaction that obeys the rate law.

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How is the density of a substance calculated?

murzikaleks [220]

Example:

sample density of gasoline, 20 g of weigth into 5 <span>mL

Answer:

D = m / V

D = 20 g / 5 mL

D = 4 g/mL</span>

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3 years ago

Balance the following redox reaction occurring in an acidic solution. The coefficient of Mn2+(aq) is given. Enter the coefficien

Vadim26 [7]

Answer:

_5_ AsO2−(aq) + 3 Mn2+(aq) + _2_ H2O(l) → _5_ As(s) + _3_ MnO4−(aq) + _4_ H+(aq)

Explanation:

Step 1:

The unbalanced equation:

AsO2−(aq) + 3 Mn2+(aq) + H2O(l) → As(s) + MnO4−(aq) + H+(aq)

Step 2:

Balancing the equation.

AsO2−(aq) + 3Mn2+(aq) + H2O(l) → As(s) + MnO4−(aq) + H+(aq)

The above equation can be balanced as follow:

There are 3 atoms of Mn on the left side of the equation and 1 atom on the right side. It can be balance by putting 3 in front of MnO4− as shown below:

AsO2−(aq) + 3Mn2+(aq) + H2O(l) → As(s) + 3MnO4−(aq) + H+(aq)

There are 12 atoms of O on the right side and a total of 3 atoms on the left side. It can be balance by putting 5 in front of AsO2− and 2 in front of H2O as shown below:

5AsO2−(aq) + 3Mn2+(aq) + 2H2O(l) → As(s) + 3MnO4−(aq) + H+(aq)

There are 4 atoms of H on the left side and 1 atom on the right side. It can be balance by putting 4 in front of H+ as shown below:

5AsO2−(aq) + 3Mn2+(aq) + 2H2O(l) → As(s) + 3MnO4−(aq) + 4H+(aq)

There are 5 atoms of As on the left side and 1 atom on the right side. It can be balance by putting 5 in front of As as shown below:

5AsO2−(aq) + 3Mn2+(aq) + 2H2O(l) → 5As(s) + 3MnO4−(aq) + 4H+(aq)

Now the equation is balanced

7 0

3 years ago

At what height above the earth surface will the gravitational acceleration be 5m

slamgirl [31]

Answer: -

The acceleration due to gravity at height r = a = GM/r²

Rearranging

r² = GM /a

= (6.674 x 10⁻¹¹ x 5.972 x 10²⁴ ) / 5

r = 8.917 x 10⁶ m

r = 8917 Km

Now Radius of earth = 6371 Km

So height = 8917 - 6371 = 2546 Km

8 0

3 years ago

Classify each of these compounds as a Brønsted-Lowry acid, a Brønsted-Lowry base, or neither.

chubhunter [2.5K]

Answer:

Brønsted-Lowry acid : H2SO4, HF, HNO2

Brønsted-Lowry Base : NH3, C3H7NH2, CH3)3N

Neither : NaBr, CCl4

Explanation:

8 0

4 years ago

A reaction between liquid reactants takes place at - 11.0 degree C in a sealed, evacuated vessel with a measured volume of 45.0

Sati [7]

Explanation:

The given data is as follows.

T = $11^{o}C$ = (11 + 273) K = 284 K, V = 45.0 L

m = 35 g

As molar mass of chlorine pentafluoride is 130.445 g/mol. Hence, number of moles of chlorine pentafluoride are as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

= $\frac{35 g}{130.445 g/mol}$

= 0.268 mol

Now, using the ideal gas equation we will find the pressure as follows.

PV = nRT

$P \times 45.0 L = 0.268 mol \times 0.082 L atm/mol K \times 284 K$

P = 0.139 atm

Thus, we can conclude that pressure of chlorine pentafluoride gas in the given reaction vessel after the reaction is 0.139 atm.

4 0

3 years ago