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2 years ago

Find the value of x and y

Mathematics

1 answer:

kifflom [539]2 years ago

6 0

The answer is option B.

If you substitute the numbers you get 40° and 110° as it's supposed to be.

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey

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1/3+1/3+1/3+1/3=4/3<br><br> is this answer correct?

natali 33 [55]

Yes but if you need it in mixed number form it’s 1 1/3

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2 years ago

Which angles are supplementary to∠4? Select all that apply.

andrezito [222]

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Answer:

B, D, E

Step-by-step explanation:

All of the acute angles are congruent to each other. All of the obtuse angles are supplementary to them and are also congruent to each other. Angles 2, 3, 6, 7 are supplementary to angle 4. The ones on the list of choices are ...

∠2, ∠6, ∠7

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2 years ago

Make a graph of the following region 1< x+y in the standard (X

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Slope of 1 dotted line

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3 years ago

What is the equation of a line that passes through the points (3, 6) and (8, 4)?

romanna [79]

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Answer:

y = -2/5x +36/5 . . . . . slope-intercept form

2x +5y = 36 . . . . . . . . standard form

Step-by-step explanation:

You can use the 2-point form of the equation of a line to find it.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

y = (4 -6)/(8 -3)(x -3) +6

y = -2/5(x -3) +6

y = -2/5x +36/5 . . . . slope-intercept form

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5 0

2 years ago

Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that s

WINSTONCH [101]

Answer: $\bold{c=\dfrac{1+\sqrt{19}}{3}\approx1.8}$

<u>Step-by-step explanation:</u>

There are 3 conditions that must be satisfied:

f(x) is continuous on the given interval
f(x) is differentiable
f(a) = f(b)

If ALL of those conditions are satisfied, then there exists a value "c" such that c lies between a and b and f'(c) = 0.

f(x) = x³ - x² - 6x + 2 [0, 3]

1. There are no restrictions on x so the function is continuous $\checkmark$

2. f'(x) = 3x² - 2x - 6 so the function is differentiable $\checkmark$

3. f(0) = 0³ - 0² - 6(0) + 2 = 2

f(3) = 3³ - 3² - 6(3) + 2 = 2

f(0) = f(3) $\checkmark$

f'(x) = 3x² - 2x - 6 = 0

This is not factorable so you need to use the quadratic formula:

$x=\dfrac{-(-2)\pm \sqrt{(-2)^2-4(3)(-6)}}{2(3)}\\\\\\.\quad =\dfrac{2\pm \sqrt{4+72}}{2(3)}\\\\\\.\quad =\dfrac{2\pm \sqrt{76}}{2(3)}\\\\\\.\quad =\dfrac{2\pm 2\sqrt{19}}{2(3)}\\\\\\.\quad =\dfrac{1\pm \sqrt{19}}{3}\\\\\\.\quad \approx\dfrac{1+4.4}{3}\quad and\quad \dfrac{1-4.4}{3}\\\\\\.\quad \approx1.8\qquad and\quad -1.1$

Only one of these values (1.8) is between 0 and 3.

5 0

2 years ago