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Alina [70]
3 years ago
10

A soccer ball is kicked with an initial horizontal velocity of 12 m/s and an initial vertical velocity of 19 m/s. 1 what is the

initial speed of the ball?
Physics
1 answer:
alex41 [277]3 years ago
5 0
22.4722050542442 maybe I am not completely sure
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A massless rod of length L has a small mass m fastened at its center and another mass m fastened at one end. On the opposite end
konstantin123 [22]

Answer:

onservation of energy

U top = K bottom

(m + m)*g*L = 1/2*I*?^2 where I = m*(L/2)^2 + m*L^2 = 1.25*m*L^2

So 2m*g*L = 1/2*1.25*m*L^2*?^2

So ? = sqrt(3*g*/(1.25*L) ) = sqrt(12g/5L)

3 0
3 years ago
The purpose of the defense is to _____.
BigorU [14]
Hello,

The purpose of the defense is to <span>prevent the opposing offense from advancing the ball.

Explanation: Defense is to defend our team or group so that the other team or group does not win or take the ball from us or even advance the ball.

Hope this helped!

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7 0
3 years ago
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What direction does current flow from a battery in a series circuit?
telo118 [61]
What's now called "Conventional current" is thought of as the flow of positive charge, from the battery's positive terminal to its negative one.

But it turns out that positive charges don't flow. The physical flow of charge is the flow of electrons. They come out of the battery's negative terminal, and carry negative charge around the circuit to the battery's positive one.
6 0
3 years ago
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Suppose a rock is dropped off a cliff with an initial speed of 0m/s. What is the rocks speed after 5 secounds, in m/s, if it enc
Tasya [4]

Answer:

The rock's speed after 5 seconds is 98 m/s.

Explanation:

A rock is dropped off a cliff.

It had an initial velocity of 0 m/s. And now it is moving downwards under the influence of gravitational force with the gravitational acceleration of 9.8 m/s².

Speed after 5 seconds = V

We know that acceleration = average speed/time

In our case,

g = ((0+V)/2)/5

9.8*5 = V/2

=> V = 2*9.8*5

V = 98 m/s

3 0
3 years ago
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A 200kg ball on the end of string is swung in horizontal circle with radius of 0.5m . The ball makes revolution every 2second th
ANEK [815]

Answer:\dfrac{\pi}{2} ms^{-1}

Explanation:

Let T be the time required to make one revolution.

Let r be the radius of the circular path.

Let d be the distance travelled by ball in one revolution.

As we know,the distance travelled in one revolution is the circumference of the circle.

So,d=2\pi r

Given,d=0.5m\\T=2sec

d=2\times \pi \times 0.5=\pi m

Speed of an object moving is circular path is define as the ratio of distance travelled in one revolution to the time taken by the object to complete one revolution.

Let s be the speed of the ball.

s=\frac{d}{T}=\frac{\pi }{2}ms^{-1}

So,the speed of the ball is \frac{\pi }{2}ms^{-1}

5 0
3 years ago
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