Ask question

Ask question

All categories

4 years ago

10

A soccer ball is kicked with an initial horizontal velocity of 12 m/s and an initial vertical velocity of 19 m/s. 1 what is the

initial speed of the ball?

1 answer:

alex41 [277]4 years ago

5 0

22.4722050542442 maybe I am not completely sure

You might be interested in

Light from a helium-neon laser (λ=633nm) passes through a circular aperture and is observed on a screen 5.80 mm behind the apert

Helga [31]

Explanation:

Whenever the light passes through hole or slit then it tends to bend that is actually a diffraction. It will then made the interference pattern of light and dark bands that due to constructive and destructive interference.

So by using the equation of diffraction,

dsinA = nL

SinA is a geometric component it can be written as,

$d\frac{y}{x} = nL$

∵ x is the distance from screen.

∵ y is the half of the width of central maximum.

now by putting the values in mm,

$d\frac{17}{5.80} = 0.000633$

d = 2.15× $10^{-4}$ mm

7 0

3 years ago

If we know the total energy in a system is 30 J, and we know the PE is 20 J. What is the KE?

svetoff [14.1K]

Can you give more description ??

3 0

3 years ago

As 390 g of hot milk cools in a mug, it transfers 30,000 J of heat to the environment. What is the temperature change of the mil

svetoff [14.1K]

We will apply:
Q = mcΔT; where Q is the heat, m is the mass, c is the specific heat capacity and ΔT is the temperature change.

30,000 = 390 x 3.9 x ΔT
ΔT = 19.7 °C

The temperature change is of 19.7 °C.

7 0

4 years ago

A plane is traveling at a velocity of 90 m/s. It accelerates at a constant rate of 1.5 m/s2 until its velocity reaches 500 m/s.

katrin2010 [14]

Answer:

The distance the plane covered while it was accelerating is 80,633.3 m

Explanation:

Given;

initial velocity of the plane, u = 90 m/s

acceleration of the plane, a = 1.5 m/s²

final velocity of the plane, v = 500 m/s

The distance covered by the plane is given as;

v² = u² + 2ad

where;

d is the distance covered by the plane;

500² = 90² + 2(1.5)d

500² - 90² = 3d

241900 = 3d

d = 241900 / 3

d = 80,633.3 m

Therefore, the distance the plane covered while it was accelerating is 80,633.3 m

5 0

3 years ago

Please do parts (a) and part (b) below and include diagrams where applicable:

Harlamova29_29 [7]

Answer:

Part a)

m = 232.1 gram

Part b)

M = 928.6 gram

Explanation:

Part a)

As we know that frequency of vibration for a given spring block system is given by formula

$f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}$

so if it is given as 0.90 Hz then we will have

$0.90Hz = \frac{1}{2\pi}\sqrt{\frac{k}{m}}$

Now if additional mass is attached with it the frequency changed to 0.50 Hz

$0.50 Hz = \frac{1}{2\pi}\sqrt{\frac{k}{m + 520}}$

now divide two equations

$\frac{0.90}{0.50} = \sqrt{\frac{m + 520}{m}}$

$3.24m = m + 520$

$m = 232.1 g$

Part b)

Now the frequency is changed to 0.45 Hz

so again we will have

$0.45 Hz = \frac{1}{2\pi}\sqrt{\frac{k}{M}}$

again divide it with first equation above

$\frac{0.90}{0.45} = \sqrt{\frac{M}{m}}$

as we know that m = 232.1 g

so total mass needed for 0.45 Hz will be

$M = 928.6 gram$

7 0

3 years ago