3. A 6 kg block moving to the right at 4 m/s collides with and sticks to a stationary block of unknown mass. If the two blocks m
1 answer:
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Answer:
the angular acceleration is 9.7 rad/
Explanation:
given information:
mass of thin rod, m = 3.2 kg
the length of the rod, L = 1.2
angle, θ = 38
to find the acceleration of the rod, we can use the torque's formula as below,
τ = Iα
where
τ = torque
I = inertia
σ = acceleration
moment inertia of this rod, I
I =
τ = F d, d = cosθ
τ = m g cosθ
now we can substitute the both equation,
τ = Iα
α = τ/I
= (m g cosθ)/(
)
= 3gcosθ/2L
= 3 (9.8)cos 38°/(2 x 1.2)
= 9.7 rad/
Answer:
44.755 m
Explanation:
Given:
Height of the movie star, H = 1.75 m = 1750 mm
Height of the image, h = - 8.25 mm
Focal length of the camera = 210 mm
Let the distance of the object i.e the distance between camera and the movie star be 'u'
and
distance between the camera focus and image be 'v'
thus,
magnification, m =
also,
m =
thus,
or
or
....................(1)
now, from the lens formula
on substituting value from (1)
or
or
u = 210 × ( 1 + 212.12 )
or
u = 44755.45 mm
or
u = 44.755 m