Answer:
I don't know about this, this is which class question
The distance is 17 and the displacement is 1
Answer:
B) 100 J
Explanation:
Assuming the distance given is measured along the incline, the vertical change in height is (5 m)(sin 30°) = 2.5 m. Then the change in potential energy is ...
∆PE = mg(∆h) = (4 kg)(10 m/s^2)(2.5 m) = 100 J
Answer: D
Explanation: read the answers above and compare to your test