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zalisa [80]
3 years ago
7

Somebody answer my questions!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! plz they are too

easy..
Physics
2 answers:
GenaCL600 [577]3 years ago
7 0

Answer:

Which questions?

Explanation:

Because I can't see your questions

nikitadnepr [17]3 years ago
3 0

Answer:

what question??/!!11?1!!11

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A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.350 m long and has a mass o
Ksju [112]

Answer:

71.4583 Hz

67.9064 N

Explanation:

L = Length of tube = 1.2 m

l = Length of wire = 0.35 m

m = Mass of wire = 9.5 g

v = Speed of sound in air = 343 m/s

The fundamental frequency of the tube (closed at one end) is given by

f=\frac{v}{4L}\\\Rightarrow f=\frac{343}{4\times 1.2}\\\Rightarrow f=71.4583\ Hz

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz

The linear density of the wire is

\mu=\frac{m}{l}\\\Rightarrow \mu=\frac{9.5\times 10^{-3}}{0.35}\\\Rightarrow \mu=0.02714\ kg/m

The fundamental frequency of the wire is given by

f=\frac{1}{2l}\sqrt{\frac{T}{\mu}}\\\Rightarrow f^2=\frac{1}{4l^2}\frac{T}{\mu}\\\Rightarrow T=f^2\mu 4l^2\\\Rightarrow T=71.4583^2\times 0.02714\times 4\times 0.35^2\\\Rightarrow T=67.9064\ N

The tension in the wire is 67.9064 N

7 0
3 years ago
A. A horse pulls a cart along a flat road. Consider the following four forces that arise in this situation.
never [62]

Answer:

a) F₁ = F₂,  F₃ = F₄,  b)  the correct answer is 3

Explanation:

a) In this exercise we have several action and reaction forces, which are characterized by having the same magnitude, but different direction and being applied to different bodies

Forces 1 and 2 are action and reaction forces F₁ = F₂

Forces 3 and 4 are action and reaction forces F₃ = F₄

as it indicates that the

b) how the car increases if speed implies that force 1> force3

      F₁ > F₃

therefore the correct answer is 3

3 0
3 years ago
The _______ theory states that the Moon formed as the result of a collision between Earth and a Marssized object.
FromTheMoon [43]
D.) giant impact

hope this helps 
4 0
3 years ago
The ___ of a gas is due to the force exerted on the walls of the
Furkat [3]

Answer:

its molecules

Explanation:

7 0
3 years ago
A golfer hits a shot to a green that is elevated 3.20 m above the point where the ball is struck. The ball leaves the club at a
dem82 [27]

Answer:

16.17 m/s

Explanation:

h = 3.2 m

u = 18.1 m/s

Angle of projection, θ = 49°

Let H be the maximum height reached by the ball.

The formula for the maximum height is given by

H=\frac{u^{2}Sin^{2}\theta }{2g}

H=\frac{18.1^{2}\times Sin^{2}49 }{2\times 9.8}=9.52 m

The vertical distance fall down by the ball, h'  H - h = 9.52 - 3.2 = 6.32 m

Let v be the velocity of ball with which it strikes the ground.

Use third equation of motion for vertical direction

v_{y}^{2}=u_{y}^{2}+2gh'

here, uy = 0

So,

v_{y}^{2}=2\times 9.8 \times 6.32

vy = 11.13 m/s

vx = u Cos 49 = 18.1 x 0.656 = 11.87 m/s

The resultant velocity is given by

v=\sqrt{v_{x}^{2}+v_{y}^{2}}

v=\sqrt{11.87^{2}+11.13^{2}}

v = 16.27 m/s

7 0
4 years ago
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