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zalisa [80]
3 years ago
7

Somebody answer my questions!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! plz they are too

easy..
Physics
2 answers:
GenaCL600 [577]3 years ago
7 0

Answer:

Which questions?

Explanation:

Because I can't see your questions

nikitadnepr [17]3 years ago
3 0

Answer:

what question??/!!11?1!!11

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yuradex [85]
The picture won’t load
5 0
3 years ago
38. You are fishing and catch a fish with a mass of
adoni [48]

Answer:

1.7333333m/s²

Explanation:

Tension of the line = the weight + force from pulling up the fish

30N = mg + ma

30 = (6)(9.8) + (6)a

10.4 = 6a

∴ a = 1.7333333m/s²

6 0
3 years ago
In the 2016 Olympics in Rio, after the 50 m freestyle competition, a problem with the pool was found. In lane 1 there was a gent
Dmitry_Shevchenko [17]

Answer:

Explanation:

A )

speed of swimming in still water is given by the expression

distance / time

= 50 / 25

= 2 m /s

In lane 1 , 1.2 cm/s current is flowing in the direction that the swimmers are going so swimmers will cover distance at the rate of  2 + 1.2 = 3.2 m /s.

time to cover distance of 50 m in lane 1

= distance / speed

= 50 / 3.2 = 15.625 s

In lane 8 , 1.2 cm/s current is flowing against  the direction that the swimmers are going so swimmers will cover distance at the rate of  2 - 1.2 = .8 m /s.

time to cover distance of 50 m in lane 1

= distance / speed

= 50 / .8 = 62.5 s

8 0
3 years ago
Suppose that a public address system emits sound uniformly in all directions and that there are no reflections . The intensity a
Marina86 [1]

Answer:

I_{2}=2.39*10^{-5} W/m^{2}

Explanation:

The definition of the intensity in terms of power is given by:

I=\frac{P}{A}

Where:

  • P is the power
  • A is the area

If the sound emits uniformly in all directions and that there are no reflections, we can assume the geometry of the wave sound is spherical.

Let's recall the area of a sphere is A = 4\pi R^{2}

To the first location we have:

I_{1}=3*10^{-4} W/m^{2}=\frac{P}{4\pi 22^{2}}

and to the second location we have:

I_{2}=\frac{P}{4\pi 78^{2}}

Now, we can divide each intensity to find the second intensity.

\frac{I_{2}}{I_{1}}=\frac{\frac{P}{4\pi 78^{2}}}{\frac{P}{4\pi 22^{2}}}

I_{2}=I_{1}* \frac{22^{2}}{78^{2}}

I_{2}=3*10^{-4}\frac{22^{2}}{78^{2}}

I_{2}=2.39*10^{-5} W/m^{2}

I hope it helps you!

     

5 0
3 years ago
Read 2 more answers
(b) Which has more mass: 50 cm of gold or 50 cm of aluminum? Explain.
monitta
Gold’s molar mass is about 196 while aluminum is about 27, thus 50cm of gold has more mass
8 0
3 years ago
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