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svetlana [45]
4 years ago
11

While John is traveling along a straight interstate highway, he notices that the mile marker reads 249 km. John travels until he

reaches the 141 km marker and then retraces his path to the 174 km marker. What is John’s resultant displacement from the 249 km marker? Answer in units of km.
Physics
1 answer:
erastova [34]4 years ago
8 0

Answer:

Explanation:

Displacement can be displayed as a vector, this because it has magnitud and direction. Because of this, we can think John's Resultant Displacement as the join of this two vectors.

The First Vector is from the 249 Km Marker to the 141 Km Marker, which give us a Vector with a Magnitude equals to 108 Km.

The Second Vector goes from 141 Km Marker to the 174 Km Marker, which give us a Vector with a Magnitude equals to 33 Km.

However is important to know the direction for each Vector, we notice that John was traveling on one direction and then he returned. This makes our Vector to have a different direction, and this means difference signs. Difference signs means substraction. So, the Third Vector will be:

Third Vector = 108 Km - 33 Km

Third Vector = 75 Km

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When can we be certain that the average velocity of an object is always equal to its instantaneous velocity?
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A girl (mass M) standing on the edge of a frictionless merry-go-round (radius R, rotational inertia I) that is not moving. She t
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a) \omega=\frac{-mvR}{I+MR^2}

b) v=\frac{-mvR^2}{I+MR^2}

Explanation:

a)

Since there are no external torques acting on the system, the total angular momentum must remain constant.

At the beginning, the merry-go-round and the girl are at rest, so the initial angular momentum is zero:

L_1=0

Later, after the girl throws the rock, the angular momentum will be:

L_2=(I_M+I_g)\omega +L_r

where:

I is the moment of inertia of the merry-go-round

I_g=MR^2 is the moment of inertia of the girl, where

M is the mass of the girl

R is the distance of the girl from the axis of rotation

\omega is the angular speed of the merry-go-round and the girl

L_r=mvR is the angular momentum of the rock, where

m is the mass of the rock

v is its velocity

Since the total angular momentum is conserved,

L_1=L_2

So we find:

0=(I+I_g)\omega +mvR\\\omega=\frac{-mvR}{I+MR^2}

And the negative sign indicates that the disk rotates in the direction opposite to the motion of the rock.

b)

The linear speed of a body in rotational motion is given by

v=\omega r

where

\omega is the angular speed

r is the distance of the body from the axis of rotation

In this problem, for the girl, we have:

\omega=\frac{-mvR}{I+MR^2} is the angular speed

r=R is the distance of the girl from the axis of rotation

Therefore, her linear speed is:

v=\omega R=\frac{-mvR^2}{I+MR^2}

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4 0
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A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave persp
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Answer:

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Explanation:

solution:

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b)

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I=P/A

So at 30 km:

I=100*10^3/657*10^3

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