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worty [1.4K]
3 years ago
8

When a heavy football player and a light one run into each other, which player hits the other with more force? Explain. Which on

e is hurt more by the collision? Explain.
Physics
1 answer:
EleoNora [17]3 years ago
7 0

Answer:

When a heavy football player and a light one run into each other, does the lighter player really exert as much force on the heavy player s the heavy player exerts on the light one. Yes. The interaction between the two players, the force each exerts on the other have equal strength.

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Think about decorative strings of lights that you might see displayed for a holiday. If the lights are on a series circuit, what
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That bulb will break insise
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4 years ago
A potter spins his wheel at 0.98 rev/s. The wheel has a mass of 4.2 kg and a radius of 0.35 m. He drops a chunk of clay of 2.9 k
Bad White [126]

Answer:

v_{f,w} = 1.791\,\frac{m}{s}, v_{f,c} = 0.972\,\frac{m}{s}

Explanation:

The situation can be modelled by applying the Principle of Angular Momentum Conservation:

I_{w} \cdot \omega_{o} = (I_{w} + I_{c})\cdot \omega_{f}

The final angular speed is:

\omega_{f} = \frac{I_{w}}{I_{w}+I_{c}}\cdot \omega_{o}

\omega_{f} = \left(\frac{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} }{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} + \frac{1}{2}\cdot (2.9\,kg)\cdot (0.19\,m)^{2}}\right)\cdot (0.98\,\frac{rev}{s} )\cdot \left(\frac{2\pi\,rad}{1\,rev}  \right)

\omega_{f} \approx 5.116\,\frac{rad}{s}

The tangential velocities of the wheel and the clay are, respectively:

v_{f, w} = (0.35\,m)\cdot (5.116\,\frac{rad}{s} )

v_{f,w} = 1.791\,\frac{m}{s}

v_{f, c} = (0.19\,m) \cdot (5.116\,\frac{rad}{s} )

v_{f,c} = 0.972\,\frac{m}{s}

5 0
3 years ago
A saddle weighs 250 newtons. The mass of the saddle is __________ kilograms. Use g = 9.8 N/kg for gravity.
Irina18 [472]

Answer:

saddle weighs 250 newtons. The mass of the saddle is ____250/9.8 kg______ kilograms. Use g = 9.8 N/kg for gravity.

7 0
2 years ago
A Van de Graaff generator causes a total charge q to build up on a metal sphere of radius r. Which variable does not affect the
Maru [420]

Answer:

The radius r of the metal sphere.

Explanation:

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What is important to notice here is that the radius of the sphere does not matter because any test charge sitting at distance R feels the force as if all the charge Q were sitting at the center of the sphere.

This situation is analogous to the gravitational field. When calculating gravitational force due to a body like the sun or the earth, we take not of only the mass of the sun and the distance from it's center; the sun's radius does not matter because we assume all of its mass to be concentrated at the center.

6 0
3 years ago
A mass weight of 120N is hung from two strings. what is the tension?
kramer
The weight should be shared between the two string equally. Therefore, tension in each string, T is;

T = 120 N/2 = 60 N
7 0
4 years ago
Read 2 more answers
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