The correct answer to the question is : A) Tossing it horizontally at a faster speed.
EXPLANATION:
Before going to answer this question, first we have to know the horizontal distance covered by any body when it is fired parallel to the ground.
Let us consider a body of mass m is fired with velocity u parallel to the ground. Let it was projected at a height h from the ground.
Hence, the horizontal distance covered by the projectile is calculated as -
Horizontal distance R = 
.
Here, g is known as the acceleration due to gravity.
From above, we see that more is the initial velocity, the more is the horizontal distance covered by it i.e the more is the widest curved path.
Hence, the correct answer to the question is that tossing a ball horizontally at a faster speed will trace out the widest curved path.
|Average acceleration| = (change in speed) / (time for the change)
Change in speed = (speed at the end) minus (speed at the beginning)
= (40 m/s) - ( 0 )
= 40 m/s .
|Average acceleration| = (40 m/s) / (60 sec) = 2/3 m/s² .
R = 10 ohm
I = 5 A
V= IR = 10 x 5 = 50 v
B is the answer!!!!!!!!!!!!!
A mass weighing 32 pounds stretches a spring 2 feet.
(a) Determine the amplitude and period of motion if the mass is initially released from a point 1 foot above the equilibrium position with an upward velocity of 6 ft/s.
(b) How many complete cycles will the mass have completed at the end of 4 seconds?
Answer:
Period = 
seconds
8 cycles
Explanation:
A mass weighing 32 pounds stretches a spring 2 feet;
it implies that the mass (m) = 
m= 
= 1 slug
Also from Hooke's Law
2 k = 32
k = 
k = 16 lb/ft
Using the function:
(because of the initial position being above the equilibrium position)
( as a result of upward velocity)
NOW, we have:
However;
means
also implies that:
Hence, 
Period can be calculated as follows:
= 
= seconds
How many complete cycles will the mass have completed at the end of 4 seconds?
At the end of 4 seconds, we have:
cycles
