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enot [183]
2 years ago
8

The mass of the moon is 7.36×1022kg and its distance to the Earth is 3.84×108m. What is the gravitational force of the moon on t

he earth?
Physics
1 answer:
marissa [1.9K]2 years ago
8 0

Answer:

The gravitational force is F =  2\,*\,10^{20}\,N

Explanation:

To answer this question we need to recall Newton's Universal Law of Gravitation for the force "F" exerted from one object to the other:

F=G\,\frac{m_1\,*\,m_2}{d^2}

where G is the Universal gravitational constant = 6.674\,* \,10^{-11}\,\,\frac{m^3}{kg\,s^2}

m_1, and m_2 are the masses of the two bodies/objects attracting each other via gravitational force. In our case, one is the mass of the Earth = 5.972\,*\,10^{24}\, kg

and the other one,the mass of the Moon = 7.36\,*\,10^{22}\,kg

and lastly, "d" is the distance between to two objects. In our case:

d =3.84\,*\,10^8\,m

Since all these quantities are given in SI units, when we use them in the formula, our answer will result in the SI units of force "N" (Newtons):

F=6.674\,*10^{-11}\,\frac{5.972\,10^{24}\,7.36\,10^{22}}{(3.84\,10^8)^2} \,N\\F=1.989\,*\,10^{20}\,N\\

which can be rounded to: F = 2\,*\,10^{20}\,N

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Answer:

\alpha =29.60

Explanation:

Let the normal force of the wall on the ladder be N2 and the normal force of the ground on the ladder be N1.

Horizontal forces:

N_{2}= (u1)(N_{1}) [1]

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Substitute [2] into [1]:

N_2 = (u1)*[m*g - (u2)(N_2)]

N_2= \frac{(u1)m*g}{[1 + (u1)(u2)]} [3]

Torques about the point where the ladder meets the ground:

m*g(\frac{L}{2})sin\alpha= (N_2)(L)cos\alpha+(u2)(N_2)(L)sin\alpha

(\frac{1}{2})*m*g=(N_2)*cot\alpha+(u2)(N_2)

[1 + (u1)(u2) - 2(u2)(u1)]/2 [1 + (u1)(u2)]= [(u1)/[1 + (u1)(u2)]]cot\alpha

tanα = \frac{2*(u1)}{1-u1*u2}

\alpha =tan^{-1}*(\frac{2*0.265}{1-0.265*0.253})

\alpha =tan^{-1}*(0.568)

\alpha =29.60

4 0
3 years ago
I'm doing something for science but I'm not sure how to answer these questions.
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Magnetism is a ?<br> A) FORCE<br> B) POWER<br> C) FORM OF ENERGY<br> D) FORM OF ELECTRICITY
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Saturated and Unsaturated Solutions
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When 30.0 g of NaCl is added to 100 ml of water, it all dissolves, forming an unsaturated solution. When 40.0 g is added, 36.0 g dissolves and 4.0 g remains undissolved, forming a saturated solution.

How can you tell if a solution is saturated or unsaturated? If more solute is added and it does not dissolve, then the original solution was saturated. If the added solute dissolves, then the original solution was unsaturated. A solution that has been allowed to reach equilibrium but which has extra undissolved solute at the bottom of the container must be saturated.
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hoa [83]
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2 years ago
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