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enot [183]
3 years ago
8

The mass of the moon is 7.36×1022kg and its distance to the Earth is 3.84×108m. What is the gravitational force of the moon on t

he earth?
Physics
1 answer:
marissa [1.9K]3 years ago
8 0

Answer:

The gravitational force is F =  2\,*\,10^{20}\,N

Explanation:

To answer this question we need to recall Newton's Universal Law of Gravitation for the force "F" exerted from one object to the other:

F=G\,\frac{m_1\,*\,m_2}{d^2}

where G is the Universal gravitational constant = 6.674\,* \,10^{-11}\,\,\frac{m^3}{kg\,s^2}

m_1, and m_2 are the masses of the two bodies/objects attracting each other via gravitational force. In our case, one is the mass of the Earth = 5.972\,*\,10^{24}\, kg

and the other one,the mass of the Moon = 7.36\,*\,10^{22}\,kg

and lastly, "d" is the distance between to two objects. In our case:

d =3.84\,*\,10^8\,m

Since all these quantities are given in SI units, when we use them in the formula, our answer will result in the SI units of force "N" (Newtons):

F=6.674\,*10^{-11}\,\frac{5.972\,10^{24}\,7.36\,10^{22}}{(3.84\,10^8)^2} \,N\\F=1.989\,*\,10^{20}\,N\\

which can be rounded to: F = 2\,*\,10^{20}\,N

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Air enters a compressor with a pressure of 14.7 lbf/in.2 , a temperature of 70F, and a volumetric flow rate of 40 ft3 /s. Air ex
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Explanation:

See attached picture.

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3 years ago
An arrow is projected by a bow vertically up with a velocity of 40 m/s, and reaches a target in 3 s. What is the velocity of the
Fittoniya [83]

Answer:

Explanation:

Step one:

given data

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Step two:

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assume g=9.81m/s^2

v=40-9.81*3

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Step three:

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s=ut-1/2gt^2

s=40*3-1/2(9.81)*3^2

s=120-88.29/2

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6 0
3 years ago
A ray of light bends upon entering a new medium. What is this phenomenon called?
hoa [83]
Ii believe it's a refraction
4 0
4 years ago
Read 2 more answers
The surface of an insulating sphere (A) is charged up uniformly with positive charge, and brought very close to an identical–siz
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Answer:

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B) there is an attraction between sphere

C) The charge of sphere A is distributed between the two spheres,

Explanation:

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with this principle let's analyze the different situations

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A negative charge of value Q is induced on sphere B

B) In this case there is an attraction between sphere A with positive charge and sphere B with negative induced charge

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