All categories

3 years ago

Discuss the symmetry between the laws of Charles Coulomb and Sir Isaac Newton regarding forces

Physics

2 answers:

marshall27 [118]3 years ago

7 0

Explanation :

(1) Charles Coulomb discovered the electrostatic force acting on two charged bodies.

According to him " the force of attraction or repulsion is directly proportional to the product of their charges and inversely proportional to the square of distance between them.''

$F=\dfrac{1}{4\pi \epsilon_0}\dfrac{q_1q_2}{r^2}$

where

$\dfrac{1}{4\pi \epsilon_0}$ is electrostatic constant.

While Sir Isaac Newton discovered the gravitational forces acting on two masses.

According to him " there exists a force in the universe which attracts every other object with a force which is equal to the product of their masses and inversely proportional to the square of the distance between them."

$F=G\dfrac{m_1m_2}{r^2}$

where,

G is universal gravitational constant.

(2) It is given that,

Charge, $q=1.25\times 10^{-19}\ N$

Force, $F=3\times 10^{-9}\ N$

We know that the relation between electric field and electric force is F = q E.

So, $E=\dfrac{F}{q}$

$E=\dfrac{3\times 10^{-9}\ N}{1.25\times 10^{-19}\ C}}$

$E=2.4\times 10^{10}\ N/C$

(3) It is given that,

Electric field, $E=2.8\times 10^4\ N/C$

Charge, $q=-4\times 10^{-6}\ C$

Since, F = q E

So, $F=-4\times 10^{-6}\ C\times 2.8\times 10^4\ N/C$

$F=-11.2\times 10^{-2}\ N$

Negative sign shows the force is attractive.

Hence, this is the required solution.

I am Lyosha [343]3 years ago

4 0

Base on the question, the answer and the explanation would be, Newton's law of gravitation has force proportional to the product of the masses of the two bodies and inversely proportional to the square of the distance between them. Coulomb's law is similar, with the charges replacing the masses; however, you can have repulsion (+)(+) or (-)(-) with electrostatics but only attraction with gravitation.

You might be interested in

A current of 15.0 A flows through an electric heater operating on 120 V. Compute the power consumption of the electric heater.

Rzqust [24]

Answer:

There will be 1800 W power consumption in heater

Explanation:

We have given current flowing in the heater I = 15 A

Voltage on which heater is operating V = 120 volt

We have to find the power consumption in the heater

We know that power consumption is given by P = VI

So power consumption in heater = 120 × 15 = 1800 W

So there will be 1800 W power consumption in heater

5 0

3 years ago

Which types of numbers does scientific notation best describe?

Travka [436]

The correct answer is
c) very small and very large

Let's see this with a few examples:
1) if we have a very small number, such as
 $0.0000000001$
we see that we can write it easily by using the scientific notation:
 $1\cdot 10^{-10}$
2) Similarly, if we have a very large number:
 $10000000000$
we see that we can write it easily by using again the scientific notation:
 $1 \cdot 10^{10}$

4 0

3 years ago

Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant

Elena L [17]

Answer:

19 m/s

Explanation:

The complete question requires the final speed to be calculated.

Velocity is the rate and direction at which an object moves. Acceleration is the rate of change of velocity per unit time and can be calculated by the difference in velocity over a given time.

For this question, first the unknown acceleration must be calculated and used to determine the final velocity

Step 1: Calculate the acceleration

$a=\frac{v_{2}-v{1}}{t_{1}}$

$a=\frac{11-7}{8}$

$a=\frac{4}{8}$

$a=0.5 m/s^{2}$

Step 2: Calculate the velocity using the acceleration calculated above

$a=\frac{v_{3}-v{2}}{t_{2}}$

$0.5=\frac{v_{3}-11}{16}$

$v_{3}=19 m/s$

3 0

3 years ago

"I could feel his anguish" what could be the anguish

sergey [27]

Answer:

yeah

Explanation:

the answer is right.

3 0

3 years ago

Calculate the specific heat at constant volume of water vapor, assuming the nonlinear triatomic molecule has three translational

vampirchik [111]

Answer:

I) $c=1385.667\frac{J}{kg K}$

II)The difference from the value obtained on part I is: 2000-1385.67 =614.33 $\frac{J}{Kg K}$

The possible reason of this difference is that the vibrational motion can increase the value, since if we take in count this factor we will have a higher heat capacity, because molecules with vibrational motion require more heat to vibrate and necessary higher specific heat capacity.

Explanation:

From the problem we have the molar mass given $M=18\frac{gr}{mol}$ of water vapor and at constant volume condition. It's important to say that the vapour molecules have 3 transitionsl and 3 rotational degrees of freedom and the rotational motion no contribution.

Part I

Calculate the specific heat at constant volume of water vapor, assuming the nonlinear triatomic molecule has three translational and three rotational degrees of freedom and that vibrational motion does not contribute. The molar mass of water is 18.0 g/mol=0.018kg/mol.

Let $C_v (\frac{J}{Kg K})$ the molar heat capacity at constant volume and this amount represent the quantity of heat absorbed by mole.

Let $C (\frac{J}{Kg K})$ the specific heat capcity this value represent the heat capacity aboserbed by mass.

For the problem we have a total of 6 degrees of freedom and from the thoery we know that for each degree of freedom the molar heat capacity at constant volume is given by $C_v =\frac{R}{2}$ so the total for the 6 degrees of freedom would be:

$C_v =6*\frac{R}{2}=3R=3x8.314\frac{J}{mol K}=24.942\frac{J}{mol K}$

And by definition we know that the specific heat capacity is defined:

$c=\frac{C_V}{M}$

If we replace all the values we have:

$c=\frac{24.942\frac{J}{mol K}}{0.018\frac{kg}{mol}}=1385.667\frac{J}{kg K}$

So on this case the specific heat capacity with constant volume and with three translational and three rotational degrees of freedom is $c=1385.667\frac{J}{kg K}$

Part II

The actual specific heat of water vapor at low pressures is about 2000 J/(kg * K). Compare this with your calculation.

The difference from the value obtained on part I is: 2000-1385.67 =614.33 $\frac{J}{Kg K}$

4 0

4 years ago