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otez555 [7]
3 years ago
8

A maroon plane has a takeoff speed of 88.3 m/s and requires 1635 m to reach that speed. Determine the acceleration of the plane

Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0
18.5164213 if you divide them both you get that number so the volceity is the number shown above.
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6. A wave has a frequency of 600 Hz and is traveling at 300 m/s. What is its<br> wavelength?
Luda [366]

Answer:

0.5m

Explanation:

v=f×lamda

v is 300m/s, f is 600Hz, lamda is ?

lamda=v/f

lamda=300/600

lamda =3/6=1/2m

5 0
2 years ago
When an object in simple harmonic motion is at its maximum displacement, its____________ is also at a maximum.
Ivan

When an object in simple harmonic motion is at its maximum displacement, its <u>acceleration</u> is also at a maximum.

<u><em>Reason</em></u><em>: The speed is zero when the simple harmonic motion is at its maximum displacement, however, the acceleration is the rate of change of velocity. The velocity reverses the direction at that point therefore its rate of change is maximum at that moment. thus the acceleration is at its maximum at this point</em>

<em />

Hope that helps!

7 0
2 years ago
How much gas is there in 100cm3 of air?
sweet [91]
<span><em>78% = nitrogen</em>

<em>21% = oxygen</em>
</span>
<em>%1  = noble gases</em>
6 0
3 years ago
Read 2 more answers
(a) How much work is required to lift a 35-kg object from the ground 3.0 m into the air? (b) How much gravitational potential en
V125BC [204]

Answer:

(a) work required to lift the object is 1029 J

(b) the gravitational potential energy gained by this object is 1029 J

Explanation:

Given;

mass of the object, m = 35 kg

height through which the object was lifted, h = 3 m

(a) work required to lift the object

W = F x d

W = (mg) x h

W = 35 x 9.8 x 3

W = 1029 J

(b) the gravitational potential energy gained by this object is calculated as;

ΔP.E = Pf - Pi

where;

Pi is the initial gravitational potential energy, at initial height (hi = 0)

ΔP.E = (35 x 9.8 x 3) - (35 x 9.8 x 0)

ΔP.E = 1029 J

7 0
2 years ago
What is the magnitude of the speed of a person at the equator due to rotational speed of the Earth?
notka56 [123]
The circumference of the Earth at the equator is listed as 24,901 miles.
So his speed is

                     24,901 miles per day.

Convert it to units that we have a better feel for:

                   (24,901 mi/da) x (1 da / 24 hrs)

             =    (24,901 / 24)  (miles/hour)

             =  about  1,038 miles per hour.

You'll find a huge number of people on the internet these days,
telling you that you could not be moving at that speed and not
feel it, so therefore the Earth is not spinning, and it's not a globe.

I have a lot of feelings and comments about those people, their
lines of reasoning, and their levels of education and intelligence,
so don't get me started.

I just want to guarantee you that everything you're learning about
the Earth and the solar system in school is well founded, and it's
all based on the life's work of some of the smartest people of the
past 300 years of human history.  Everything you're taught about
the Earth has good reasons behind it, whereas those other people
have nothing.

A person on Earth's equator is moving from west to east at roughly
1,038 miles per hour, relative to any point on the Earth's rotation axis.
4 0
3 years ago
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