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Ray Of Light [21]
3 years ago
5

This thermogram shows a person using a computer. Complete the sentence to describe the flow of thermal energy between the person

and the computer.
Thermal energy will flow from the

to the

.
Chemistry
2 answers:
Alex787 [66]3 years ago
5 0
From the computer to the person
sergejj [24]3 years ago
4 0
<h2>Answer : The thermal energy will flow from the computer to the person.</h2><h3>Explanation :</h3>

Usually computer are such devices which converts electrical energy into thermal energy and then it gets transferred to the person. The energy flows from the higher amount to lower amount. In this case, computer is producing higher thermal energy than the person that's the reason for the flow of energy from computer to the person.

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pesticides and fertilizers can help farmers to produce more crops. However, overuse of these chemicals can result in?
nadezda [96]
Overuse of the same chemicals can result in the pest becoming immune to the pesticides. 
8 0
3 years ago
7.) A syringe initially holds a sample of gas with a volume of 285 mL at 355 K and 1.88 atm. To
marysya [2.9K]

Answer:

T₂ = 721 k

Explanation:

Given data:

Initial volume = 285 mL

Initial pressure = 1.88 atm

Initial temperature = 355 K

Final temperature = ?

Final volume = 435 mL

Final pressure = 2.50 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂  

T₂  =  P₂V₂ T₁  / P₁V₁

T₂ = 2.50 atm × 435 mL × 355 K / 1.88 atm × 285 mL  

T₂ = 386062.5 atm. mL. K /535.8 atm. mL

T₂ = 721 k

5 0
3 years ago
Earth is one of the planets in the ​
prisoha [69]

Answer:

moon obviously

Explanation:

........

6 0
3 years ago
Read 2 more answers
Answer the following questions about the fermentation of glucose (C6H12O6, molar mass 180.2 g/mol)
Yuri [45]

The amount of energy in kilocalories released from 49 g of glucose given the data is -4.4 Kcal

How to determine the mole of glucose

Mass of glucose = 49 g

Molar mass of glucose = 180.2 g/mol

Mole of glucose = ?

Mole = mass / molar mass

Mole of glucose = 49 / 180.2

Mole of glucose = 0.272 mole

How to determine the energy released

C₆H₁₂O₆ →2C₂H₆O + 2CO₂  ΔH = -16 kcal/mol

From the balanced equation above,

1 mole of glucose released -16 kcal of energy

Therefore,

0.272 mole of glucose will release = 0.272 × -16 = -4.4 Kcal

Thus, -4.4 Kcal were released from the reaction

Learn more about stoichiometry:

brainly.com/question/14735801

#SPJ1

6 0
2 years ago
Calculate the molar mass of a solute in a 1.30 L solution with of 0.50 M
Veronika [31]

Answer: 16 g/mol

Explanation: Molarity is Moles/Liters or Mol/L

(0.50 mol/L)(1.30L) = 0.65mol

(cancels out L)

Molar mass is g/mol so...

10.5g/0.65mol = 16.1 g/mol

Rounded to 2 sig figs is 16 g/mol

6 0
3 years ago
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