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kirill115 [55]
3 years ago
10

A solution is prepared by dissolving 38.6 g sucrose (C12H22O11) in 495 g of water. Determine the mole fraction of sucrose if the

final volume of the solution is 508 mL.
Chemistry
1 answer:
stiks02 [169]3 years ago
8 0

Answer:

4.09×10⁻³ is the mole fraction of sucrose

Explanation:

Mole fraction = Moles of solute or solvent/ Total moles

Let's convert the mass to moles (mass / molar mass)

38.6 g / 342 g/m = 0.113 moles of sucrose

495 g / 18 g/m = 27.5 moles of water

Total moles = 0.113 m + 27.5 m = 27.0613 moles

Mole fraction of sucrose = Moles of sucrose / Total moles

0.113 m / 27.0613 moles = 4.09×10⁻³

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If 3.68 grams of zinc were allowed to react with excess hydrochloric acid to produce zinc chloride and hydrogen gas, how much zi
AysviL [449]

Answer:

Here... Since there is excess HCl, you know the Zinc will be the limiting reagent.  I was able to create the reaction equation based on the info you gave: Z + 2HCl ----> ZCl2 +2H.  Now, in order to find the theoretical yield of ZCl, you need to convert Zinc from grams to moles.  Do this by dividing by its molar mass (65.38), thus: 3.68 (g) / 65.38 (g/mol) = 0.056286... moles.  

Now, using the balanced equation we made earlier, we see that 1 mole of Zinc creates 1 mole of ZCl2.  Thus our ratio is 1:1.  This makes the next step easy.  Since it is 1:1, we multiply the number of moles we have of Zinc (0.056286...) by the number of moles it will create of ZCl (1).  (0.056286)(1) = 0.056286 moles ZCl.  Now convert this to grams by multiplying by its molar mass (136.28) and you get 7.67 grams.  This is your theoretical yield.  The percent yield is found by dividing the actual amount obtained (7.12 g.) by the theoretical yield (7.67 g.) then multiply that by 100%.   When this is done, your Percent Yield is about 92.8%

6 0
3 years ago
If there are 3 moles of hydrogen, 6 moles of oxygen, and 9 moles of helium in a 10 L vessel at 27°C, the total pressure of the g
harkovskaia [24]

Answer:

The correct answer is D) 44 atm

Explanation:

We apply Dalton's law, where for a gas mixture the total pressure is the sum of the partial pressures of each gas that makes up that mixture. You can add the amount of moles and then calculate the pressure, using the ideal gas formula. We convert the temperature in Celsiud into Kelvin : 0°C= 273K---->

27°C=27 + 273= 300K

PV= (nH+ n0+ nHe)x RT

P=((nH+ n0+ nHe)x RT)/V=

P=((3 mol + 6 mol +9 mol)x 0,082 l atm/ Kmol x300K)/10 L

<em>P=44, 28 atm</em>

4 0
3 years ago
What term defines a mass which is exactly equal to 1/12 the mass of one carbon-12 atom
aalyn [17]

Answer:

Relative atomic mass and it is expressed in atomic mass unit (amu)

Explanation:

AMU:

Atomic mass unit is define as the 1/12 the mass of an atom of carbon-12.

C12 has six neutron and six protons in the nucleus.

This unit is used to express the masses of atoms. We know that masses of atoms are very small and we do not have any such type of balance that can measure very small quantity. So that is way we use this scale to measure small quantity. For example, according to this scale

relative atomic mass of hydrogen is 1.008 amu

relative atomic mass of oxygen is 15.999 amu

relative atomic mass of uranium is 238.0289 amu

relative atomic mass of chlorine is 35.453 amu

4 0
3 years ago
HELP.
Kamila [148]

Answer:

The mass of tin is 164 grams

Explanation:

Step 1: Data given

Specific heat heat of tin = 0.222 J/g°C

The initial temeprature of tin = 80.0 °C

Mass of water = 100.0 grams

The specific heat of water = 4.184 J/g°C

Initial temperature = 30.0 °C

The final temperature = 34.0 °C

Step 2: Calculate the mass of tin

Heat lost = heat gained

Qlost = -Qgained

Qtin = -Qwater

Q = m*c*ΔT

m(tin)*c(tin)*ΔT(tin) = -m(water)*c(water)*ΔT(water)

⇒with m(tin) = the mass of tin = TO BE DETERMINED

⇒with c(tin) = the specific heat of tin = 0.222J/g°C

⇒with ΔT(tin) = the change of temperature of tin = T2 - T1 = 34.0°C - 80.0°C = -46.0°C

⇒with m(water) = the mass of water = 100.0 grams

⇒with c(water) = the specific heat of water = 4.184 J/g°C

⇒with ΔT(water) = the change of temperature of water = T2 - T1 = 34.0° C - 30.0 °C = 4.0 °C

m(tin) * 0.222 J/g°C * -46.0 °C = -100.0g* 4.184 J/g°C * 4.0 °C

m(tin) =  163.9 grams ≈ 164 grams

The mass of tin is 164 grams

4 0
3 years ago
Dehydration of 2-methyl-2-pentanol forms one major and one minor organic product. Draw the structures of the two organic product
Korvikt [17]

Answer:

The major product is 2-methyl-2-pentene [ CH₃-CH₂-CH=C(CH₃)₂ ] and a minor product 2-methyl-1-pentene [ CH₃-CH₂-CH₂-C(CH₃)=CH₂ ].

Explanation:

Dehydration reaction is a reaction in which a molecule loses a water molecule in the presence of a dehydrating agent like sulfuric acid (H₂SO₄).

<u>Dehydration reaction of 2-methyl-2-pentanol</u> gives a major product 2-methyl-2-pentene and a minor product 2-methyl-1-pentene.

CH₃-CH₂-CH₂-C(CH₃)₂-OH (2-methyl-2-pentanol)→ CH₃-CH₂-CH=C(CH₃)₂ (2-methyl-2-pentene, major) + CH₃-CH₂-CH₂-C(CH₃)=CH₂ (2-methyl-1-pentene, minor)

<u>Since more substituted alkene is more stable than the less substituted alkene. So, the trisubstituted alkene, 2-methyl-2-pentene is more stable than the disubstituted alkene, 2-methyl-1-pentene.</u>

<u>Therefore, the trisubstituted alkene, 2-methyl-2-pentene is the major product and the disubstituted alkene, 2-methyl-1-pentene is the minor product.</u>

7 0
3 years ago
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