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Pani-rosa [81]
2 years ago
11

Describe the graph of a quadratic function

Mathematics
2 answers:
maw [93]2 years ago
7 0
So, given a quadratic function, y = ax2<span> + bx + c, when "a" is positive, the </span>parabola<span> opens upward and the vertex is the </span>minimum<span> value. On the other hand, if "a" is negative, the graph opens </span>downward<span> and the vertex is the </span>maximum<span> value. To put it in complicated terms. Or when A is positive the graph is shaped like a U but if A is negative the graph is an upside down U


</span>
Nat2105 [25]2 years ago
4 0
Graphs: Hope this helps

A quadratic function is one of the form f(x) = ax2 + bx + c, where a, b, and c are numbers with a not equal to zero.

The graph of a quadratic function is a curve called a parabola. Parabolas may open upward or downward and vary in "width" or "steepness", but they all have the same basic "U" shape. 


´

Graphs of quadratic functions have a unique symmetrical nature<span> with a maximum or minimum function value corresponding to the vertex.
</span>

´When the leading coefficient of the quadratic expression representing the function is negative the graph opens down and when positive it opens up.

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a.y'=-1

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Step-by-step explanation:

We are given that consider a function

3x+3y=8

Implicit function: That function is a relation in which dependent variable can not be expressed in terms of independent variable

Explicit function: It is that function in which dependent variable can be expressed in terms of independent variable.

a.3x+3y=8

Differentiate w.r.t x then we get

3+3\frac{dy}{dx}=0

3\frac{dy}{dx}=-3

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\frac{dy}{dx}=y'=-1

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y=\frac{8-3x}{3}

Differentiate w.r.t x then we get

\frac{dy}{dx}=\frac{-3}{3}=-1

\frac{dy}{dx}=y'=-1

When we substituting the value of y obtained from part b into a solution of part a then we get

y'=-1

Hence, solutions are consistent.

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Answer:

4.8278117e+22

Step-by-step explanation:

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3 years ago
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3 years ago
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