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ICE Princess25 [194]
3 years ago
12

A cell phone company

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
6 0

Answer:

C = 20 + 0.001x

C = $20 + $0.001x

Step-by-step explanation:

Let x represent the number of minutes spent talking on the phone.

Given;

Fixed monthly charge F = $20

Charge per 10 minutes V = $0.01

Charge per minute = V/10 = $0.01/10 = $0.001

The equation to model the cost of a monthly cell phone bill;

Total cost = fixed cost + variable cost

C = F + (V/10)x

Substituting the values;

C = 20 + 0.001x

You might be interested in
This graph shows the temperature of a room over time.
Arturiano [62]

Answer:

<u>The correct answer is C. Aaron turns on the heat and the temperature of a conference room steadily increases. After the room becomes a comfortable temperature, Aaron turns off the heat and the temperature in the room stays the same for a while. Aaron’s coworker says it is too hot in the room, so Aaron turns on the air conditioner. The temperature in the room steadily decreases. Aaron gets cold again and turns the heat back on so that the temperature of the room steadily increases. Again, when the room becomes comfortable, Aaron turns off the heat and the temperature of the room stays the same.</u>

Step-by-step explanation:

1. Let's see what happens in the conference room the first 20 minutes, according to the graph:

The temperature increase from 65 °F to 75 °F. This fact discards immediately answer B, that mentions that "the temperature of the room decreases steadily to a comfortable temperature".

2. Let's see what happens in the conference room the next 20 minutes (between minutes 20 and 40), according to the graph:

The temperature remains at 75 °F, at a comfortable temperature, during these 20 minutes. This fact discards answer D because it mentions that the "room becomes too hot", which is not true because the additional 10 °F of increase is most likely, not "too much" and it also considers 65 °F as "too cold".

3. Let's see what happens in the conference room between minutes 40 and 50, according to the graph:

In ten minutes, the temperature decreases from 75 °F to 65 °F, which was the original temperature of the room. No big difference between answers A and C, the only that are still valid.

4. Let's see what happens in the conference room between minutes 50 and 80, according to the graph:

In these 30 minutes, the temperature of the conference room again increases between minutes 50 and 70 from 65 °F to 75 °F. This last fact discards the answer A, that mentions that " finally, Aaron turns the heat back on and the temperature of the room increases steadily for the rest of the conference". What actually happened is that the temperature becomes comfortable again and stays the same the rest of the conference.

<u>This is a detailed explanation why we discard answers A, C and D and we select answer C as the right one.</u>

6 0
3 years ago
I need Help Fast Asap​
Klio2033 [76]

Answer:

C. 7.5

Hope it helps you

7 0
3 years ago
Can you help? Find the distance between A(8,3) and B(9,0) to the nearest hundredth.​
frez [133]

Answer:

3.16

Step-by-step explanation:

distance = \sqrt{(8-9)^{2} +(3-0)^{2} }

=\sqrt{1^{2}  +3^{2} }

=\sqrt{1+9}

=\sqrt{10}

=3.16

8 0
3 years ago
Solve the system using substitution.
Iteru [2.4K]
Q=2p+1
subsitute 2p+1 for q in other eqaution


4p+2q=8
4p+2(2p+1)=8
4p+4p+2=8
8p+2=8
minus 2 both sides
8p=6
divide both sides by 8
p=6/8
p=3/4
sub back
q=2p+1
q=2(3/4)+1
q=6/4+1
q=3/2+1
q=3/2+2/2
q=5/2


p=3/4
q=5/2
8 0
3 years ago
Of all customers purchasing automatic garage-door openers, 75% purchase Swedish model. Let X = the number among the next 15 purc
Lelechka [254]

Answer:

a)

P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}

For any integer k between 0 and 15, and 0 for other values of k.

b)

P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865

c) P(6 ≤ X ≤ 10) = 0.2737

d)  μ = 15*0.75 = 11.25. σ² = 11.25*0.25 = 2.8125

Step-by-step explanation:

X is a binomial random variable with parameters n = 15, p = 0.75. Therefore

a)

P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}

For any integer k between 0 and 15, and 0 for other values of k.

b)

P(X>10) = P(X=11) + P(X=12)+ P(X=13)+P(X=14)+P(x=15)

P(X=11) = {15 \choose 11} * 0.75^{11} * 0.25^4 = 0.2252

P(X=12) = {15 \choose 12} * 0.75^{12} * 0.25^3 = 0.2252

P(X=13) = {15 \choose 13} * 0.75^{13} * 0.25^2 = 0.1559

P(X=14) = {15 \choose 14} * 0.75^{14} * 0.25 = 0.0668

P(X=15) = {15 \choose 15} * 0.75^{15} = 0.0134

Thus,

P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865

c) P(6 ≤ X ≤ 10) = P(X = 6) + P(X = 7) + P(X = 8) + P(X=9) + P(X=10)

P(X=6) = {15 \choose 6} * 0.75^{6} * 0.25^9 = 0.0034

P(X=7) = {15 \choose 7} * 0.75^{7} * 0.25^8 = 0.0131

P(X=8) = {15 \choose 8} * 0.75^{8} * 0.25^7 = 0.0393

P(X=9) = {15 \choose 9} * 0.75^{9} * 0.25^6 = 0.0918

P(X=10) = {15 \choose 10} * 0.75^{10} * 0.25^{5} = 0.1652

Thereofre,

P(6 \leq X \leq 10) = 0.0034 + 0.0134 + 0.0393 + 0.0918 + 0.1652 = 0.2737

d)  μ = n*p =  15*0.75 = 11.25

σ² = np(1-p) = 11.25*0.25 = 2.8125

3 0
3 years ago
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