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3 years ago

12 dogs decreased by 25%

Mathematics

1 answer:

masya89 [10]3 years ago

7 0

Answer:

Step-by-step explanation:

12-.25(12)=12-3

12-3=9

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A runner passes the 12-mi point after 2 hours and reaches the 15-mi point 30 minutes later. Assuming a constant rate, find th

Arturiano [62]

Answer:

6 mph

Step-by-step explanation:

Difference in distance

= 15 - 12

= 3 mi

time taken

= 30 mins

= 1/2 hour

Speed

= 3 ÷ 1/2

= 6 mph

8 0

3 years ago

Round 0.971 to the nearest tenth

Flura [38]

Answer:

1.0

Step-by-step explanation:

You are rounding to the nearest tenth, so you should have only 2 places remaining (0.0). So, you look to the 7 to change the 9. 7 is bigger than 5, so you round 9 up. Since 9 plus 1 equals 10, the final answer is 1.0.

Hope this helps! :)

5 0

3 years ago

Read 2 more answers

Find the 2th term of the expansion of (a-b)^4.

vladimir1956 [14]

The second term of the expansion is $-4a^3b$ .

Solution:

Given expression:

$(a-b)^4$

To find the second term of the expansion.

$(a-b)^4$

Using Binomial theorem,

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here, a = a and b = –b

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

Substitute i = 0, we get

$$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4$

Substitute i = 1, we get

$$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b$

Substitute i = 2, we get

$$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}$

Substitute i = 3, we get

$$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}$

Substitute i = 4, we get

$$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}$

Therefore,

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

$=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}$ $=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}$

Hence the second term of the expansion is $-4a^3b$ .

3 0

3 years ago

What is the formula for the circumference of a circle?

Juli2301 [7.4K]

Answer:

C = pi * d = 2 * pi *r

Step-by-step explanation:

The circumference of a circle is the distance around the circle. It can be found by multiplying the diameter times pi.

C = pi * d

We can replace the diameter with twice the radius

C = pi * 2 * r = 2 * pi *r

5 0

3 years ago

Which of the following expressions represents the distance between 3/4 and 2

Anettt [7]

Answer:

Im not sure what the following expressions are but the answer to the distance between 3/4 and 2 is 5/4 or just 1 1/4...

Not sure if this was what you were trying to ask but hope this helps

6 0

3 years ago