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3 years ago

Rocks that are formed as a result of deposits from weathering and erosion

Physics

1 answer:

zimovet [89]3 years ago

8 0

<h2>Answer: Sedimentary rocks </h2>

Sedimentary rocks are formed from sediments and deposits of particles of various types, forms and sizes that are transported by air, wind or water, and then subjected to chemical processes to become rocks.

These types of rocks are usually found in the form of layers or strata in places where sediment accumulates due to the erosion of other materials, for example on the banks of rivers, in valleys, lakes (and any other type of body of water).

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The temperature differences seen between quito, ecuador, and guayaquil, ecuador, illustrate the effect of _____. ocean currents

Leya [2.2K]

The answer is altitude(:

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3 years ago

Read 2 more answers

An AC voltage source has an output of ∆V = 160.0 sin(495t) Volts. Calculate the RMS voltage. Tries 0/20 What is the frequency of

kupik [55]

Answer:

RMS voltage is 113.1370 V

frequency is 780.685 Hz

voltage is −158.66942 V

maximum current is 2.9739 A

Explanation:

Given data

∆V = 160.0 sin(495t) Volts

so Vmax = 160

and angular frequency = 495

time t = 1/106 s

resistor R = 53.8 Ω

to find out

RMS voltage and frequency of the source and voltage and maximum current

solution

we know voltage equation = Vmax sin ωt

here Vmax is 160 as given equation in question

so RMS will be Vmax / √2

RMS voltage = 160/ √2

RMS voltage is 113.1370 V

and frequency = angular frequency / 2π

so frequency = 497 / 2π

frequency is 780.685 Hz

voltage at time (1/106) s

V(t) = 160.0 sin(495/ 108)

voltage = −158.66942 V

so current from ohm law at resistor R 53.8 Ω

maximum current = voltage max / resistor

maximum current = 160 / 53.8

maximum current = 2.9739 A

8 0

3 years ago

A 50-loop circular coil has a radius of 3 cm. It is oriented so that the field lines of a magnetic field are perpendicular to th

nikitadnepr [17]

Answer:

-17.8 V

Explanation:

The induced emf in a coil is given as:

$E = \frac{-NdB\pi r^2}{dt}$

where N = number of loops

dB = change in magnetic field

r = radius of coil

dt = elapsed time

From the question:

N = 50

dB = final magnetic field - initial magnetic field

dB = 0.35 - 0.10 = 0.25 T

r = 3 cm

dt = 2 ms = 0.002 secs

Therefore, the induced emf is:

$E = \frac{-50 * 0.25 * \pi * 0.03^2}{0.002} \\E = -17.8 V$

Note: The negative sign implies that the EMf acts in an opposite direction to the change in magnetic flux.

6 0

3 years ago

A car moves at a constant velocity of 30 m/s and has 3.6 × 105 J of kinetic energy. The driver applies the brakes and the car st

LekaFEV [45]

The force needed to the stop the car is -3.79 N.

Explanation:

The force required to stop the car should have equal magnitude as the force required to move the car but in opposite direction. This is in accordance with the Newton's third law of motion. Since, in the present problem, we know the kinetic energy and velocity of the moving car, we can determine the mass of the car from these two parameters.

So, here v = 30 m/s and k.E. = 3.6 × 10⁵ J, then mass will be

$K.E = \frac{1}{2} * m*v^{2} \\\\m = \frac{2*KE}{v^{2} } = \frac{2*3.6*10^{5} }{30*30}=800 kg$

Now, we know that the work done by the brake to stop the car will be equal to the product of force to stop the car with the distance travelled by the car on applying the brake.Here it is said that the car travels 95 m after the brake has been applied. So with the help of work energy theorem,

Work done = Final kinetic energy - Initial kinetic energy

Work done = Force × Displacement

So, Force × Displacement = Final kinetic energy - Initial Kinetic energy.

$Force * 95 = 0-3.6*10^{5}\\ \\Force =\frac{-3.6*10^{5} }{95}=-3.79 N$

Thus, the force needed to the stop the car is -3.79 N.

5 0

3 years ago

Find the speed of a satellite in a circular orbit around the Earth with a radius 3.57 times the mean radius of the Earth. (Radiu

madam [21]

The speed of the satellite in a circular orbit around the Earth is 1.32 x 10⁵ m/s.

<h3>Speed of the satellite</h3>

v = √(GM/r)

where;

G is universal gravitation constant
M is mass of Earth
r is radius of the satellite

v = √(6.67 x 10⁻¹¹ x 5.98 x 10²⁴/3.57 x 6.37x 10³)

v = 1.32 x 10⁵ m/s

Thus, the speed of the satellite in a circular orbit around the Earth is 1.32 x 10⁵ m/s.

Learn more about speed of satellite here: brainly.com/question/22247460

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2 years ago