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Sloan [31]
3 years ago
7

What is the value of the discriminant, b2 − 4ac, for the quadratic equation 0 = x2 − 4x + 5, and what does it mean about the num

ber of real solutions the equation has? The discriminant is −4, so the equation has 2 real solutions. The discriminant is −4, so the equation has no real solutions. The discriminant is 35, so the equation has 2 real solutions. The discriminant is 35, so the equation has no real solutions.
Mathematics
2 answers:
Sedaia [141]3 years ago
6 0
Discriminant, D = b² - 4ac

x² - 4x + 5 = 0  comparing to  ax² + bx + c = 0

a = 1, b = -4, c = 5

D = b² - 4ac = (-4)² - 4*1*5 = 16 - 20 = -4

In taking the square root of the discriminant of -4, √-4 = 2i = Not Real. So:

Discriminant is -4, so the equation has no real roots.

The second option is correct.   
34kurt3 years ago
4 0
D = 16-20 = -4 

what mean exactly the second choice is right so the quadratic has no real solutions 
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statuscvo [17]
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4 0
3 years ago
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What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?
lbvjy [14]

Answer:

The equation of the quadratic graph is f(x)= - (1/8) (x-3)^2 + 3 (second option)

Step-by-step explanation:

Focus: F=(3,1)=(xf, yf)→xf=3, yf=1

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The directix y=5 must intercept the axis of the parabola at the point (3,5), and the vertex is the midpoint between this point and the focus:

Vertex is the midpoint between (3,5) and (3,1):

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Vertex: V=(h,k)→V=(3,3)

p=yf-k→p=1-3→p=-2

Replacing the values in the equation:

f(x)= [ 1 / (4(-2)) ] (x-3)^2 + 3

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4 0
3 years ago
Help me with the first one please
natulia [17]
D- 2x-1
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6 0
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8 0
3 years ago
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There are four terms
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3 years ago
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