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Sloan [31]
3 years ago
7

What is the value of the discriminant, b2 − 4ac, for the quadratic equation 0 = x2 − 4x + 5, and what does it mean about the num

ber of real solutions the equation has? The discriminant is −4, so the equation has 2 real solutions. The discriminant is −4, so the equation has no real solutions. The discriminant is 35, so the equation has 2 real solutions. The discriminant is 35, so the equation has no real solutions.
Mathematics
2 answers:
Sedaia [141]3 years ago
6 0
Discriminant, D = b² - 4ac

x² - 4x + 5 = 0  comparing to  ax² + bx + c = 0

a = 1, b = -4, c = 5

D = b² - 4ac = (-4)² - 4*1*5 = 16 - 20 = -4

In taking the square root of the discriminant of -4, √-4 = 2i = Not Real. So:

Discriminant is -4, so the equation has no real roots.

The second option is correct.   
34kurt3 years ago
4 0
D = 16-20 = -4 

what mean exactly the second choice is right so the quadratic has no real solutions 
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To calculate the distance between two points, we can use a formula that is a variation Pythagorean Theorem. Look:


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Let's go to the calculations.


\mathsf{d=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}}\\\\ \mathsf{d=\sqrt{(5-2)^2+(9-3)^2}}\\\\ \mathsf{d=\sqrt{(3)^2+(6)^2}}\\\\ \mathsf{d=\sqrt{9+36}}\\\\ \mathsf{d=\sqrt{45}}\\\\ \mathsf{d=6.7082039324993690892275210061938...}\\\\ \underline{\mathsf{d\approxeq6.7}}



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3 years ago
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Step-by-step explanation:

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Number of possible outcome for tossing N coins = 2^N

Solution:

Possible outcomes when tossing one coin = {H, T}

Number of possible outcomes when tossing one coin = 2 =2^1

Possible outcomes when tossing two coins = {HH, HT, TH, TT}

Number of possible outcomes when tossing two coins = 4 =2^2

Possible outcomes when tossing three coins

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Number of possible outcomes when tossing three coins = 8 =2^3

Therefore, the sequence obtained is 2^1, 2^2, 2^3.

If continue this sequence, we can obtain number of possible outcome for tossing N coins is 2^N.

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