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Gala2k [10]
3 years ago
13

If 1.00L of water is added to 3.00 L

Chemistry
1 answer:
Bezzdna [24]3 years ago
6 0

Answer:

4.5M

Explanation:

Here is why:

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4, 16,

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7 0
3 years ago
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1. A 5.455-g sample of impure CaCl2 is dissolved and treated with excess potassium carbonate solution. The dried CaCO3 (calcium
Helen [10]

Answer:81.6%

Explanation:

Mass of CaCO3=4.010 g

Molar mass of CaCO3= 40+12+(16×3) = 100 g/mol.

Recall: number of moles(n)= mass÷ molar mass.

n=4.010÷100 = 0.0401 mol.

Molar mass of CaCl2 = 40+71= 111 g/mol.

Number of mol of CaCl2 = 5.455÷111= 0.04914 g/mol.

Mass of CaCl2 = 0.0401 × 111 = 4.4511 g of CaCl2.

Percent by mass of CaCl2 = (4.4511÷5.455) × 100

= 0.815967 ×100 = 81.5967%

Approximately; 81.6%.

8 0
4 years ago
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