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Gala2k [10]
3 years ago
13

If 1.00L of water is added to 3.00 L

Chemistry
1 answer:
Bezzdna [24]3 years ago
6 0

Answer:

4.5M

Explanation:

Here is why:

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In the reaction of sodium with bromine, explain which atom is reduced.
atroni [7]

Answer:

The reduced atom is Br.

Explanation:

  • The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
  • The oxidation process is the process in which electrons are lost and produce positively charged ions.
  • The reduction process is the process in which electrons is gained and negatively charge ions are produced.

  • In the reaction of chlorine with calcium:

<em>2Na + Br₂ → 2NaBr, </em>

<em></em>

Na loses 1 electrons and is oxidized to Na⁺. (Na → Na⁺ + e).

Br₂ gains 2 electrons and is reduced to 2Br⁻. (Br₂ + 2e → 2Br⁻).

<em>So, the reduced atom is Br.</em>

4 0
4 years ago
Helium is listed as a noble gas true or false
Nonamiya [84]
True; Heilum is in Group 18 which are called “Noble Gases”
5 0
4 years ago
Answer this pls thanks
allsm [11]

Answer:  It is element nitrogen. It has an atomic number of 7 and the valence electron is 5. It needs 3 electrons to complete its octet state. That's why sometimes it has the oxidation number of -3 in ammonia.

6 0
3 years ago
Read 2 more answers
Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0 C, the pr
Paladinen [302]

The question is incomplete, here is the complete question:

Gaseous compound Q contains only xenon and oxygen. When a 0.100 g sample of Q is placed in a 50.0-mL steel vessel at 0°C, the pressure is 0.230 atm. What is the likely formula of the compound?

A. XeO

B. XeO_4

C. Xe_2O_2

D. Xe_2O_3

E. Xe_3O_2

<u>Answer:</u> The chemical formula of the compound is XeO_4

<u>Explanation:</u>

To calculate the molecular weight of the compound, we use the equation given by ideal gas equation:

PV = nRT

Or,

PV=\frac{w}{M}RT

where,

P = Pressure of the gas = 0.230 atm

V = Volume of the gas  = 50.0 mL = 0.050 L     (Conversion factor:  1 L = 1000 mL)

w = Weight of the gas = 0.100 g

M = Molar mass of gas  = ?

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gas = 0^oC=273K

Putting value in above equation, we get:

0.230\times 0.050=\frac{0.100}{M}\times 0.0821\times 273\\\\M=\frac{0.100\times 0.0821\times 273}{0.230\times 0.050}=194.9g/mol\approx 195g/mol

The compound having mass as calculated is XeO_4

Hence, the chemical formula of the compound is XeO_4

5 0
4 years ago
Chose the molecular formula that represents an organic molecule.
Yuri [45]
All organic molecules must have carbon and hydrogen so it would be choice A
3 0
3 years ago
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