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frozen [14]
3 years ago
5

Cacodyl, which has an intolerable garlicky odor and is used in the manufacture of cacodylic acid, a cotton herbicide, has a mass

percentage composition of 22.88% C, 5.76% H, and 71.36% As and a molar mass of 209.96 g/mol. What is the molecular formula of cacodyl?
Chemistry
1 answer:
Papessa [141]3 years ago
3 0

Answer:

The molecular formula of cacodyl is C₄H₁₂As₂.

Explanation:

<u>Let's assume we have 1 mol of cacodyl</u>, in that case we'd have 209.96 g of cacodyl and the<u> following masses of its components</u>:

  • 209.96 g * 22.88/100 = 48.04 g C
  • 209.96 g * 5.76/100 = 12.09 g H
  • 209.96 g * 71.36/100 = 149.83 g As

Now we convert those masses into moles:

  • 48.04 g C ÷ 12 g/mol = 4.00 mol C
  • 12.09 g H ÷ 1 g/mol = 12.09 mol H
  • 149.83 g As ÷ 74.92 g/mol = 2.00 mol As

Those amounts of moles represent the amount of each component in 1 mol of cacodyl, thus, the molecular formula of cacodyl is C₄H₁₂As₂.

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Use the following equation to answer the questions below.
notsponge [240]

Answer:

202

Explanation:

7 0
2 years ago
What is the Molarity of a solution of HNO3 if it contains 12.6 moles in a<br> 0.75 L solution? *
Korolek [52]

Answer:

M = 16.8 M

Explanation:

<u>Data:</u> HNO3

moles = 12.6 moles

solution volume = 0.75 L

Molarity is represented by the letter M and is defined as the amount of solute expressed in moles per liter of solution.

M=\frac{moles}{solution volume}

The data is replaced in the given equation:

M=\frac{12.6 mol}{0.75L}=16.8\frac{mol}{L}

7 0
3 years ago
Read 2 more answers
A compound containing Na, C, and O is found to have 1.06 mol Na, 0.528 mol C, and 1.59 mol O. What is the empirical formula of t
Effectus [21]

Given :

Moles of Na : 1.06

Moles of C : 0.528

Moles of O : 1.59

To Find :

The empirical formula of the compound.

Solution :

Dividing moles of each atom with the smallest one i.e 0.528 .

So,

Na : 1.06/0.528 = 2.007 ≈ 2

C : 0.528/0.528 = 1

O : 1.59/0.528 = 3.011 ≈ 3

Rounding all them to nearest integer, we will get the number of each atom in the empirical formula.

So, empirical formula is Na_2CO_3 .

Hence, this is the required solution.

5 0
2 years ago
You decide to clean the bathroom. You notice that the shower is covered in a strange green slime . you try to get rid of this sl
Free_Kalibri [48]
  1. The independent variable (IV) is the lemon juice mixture
  2. The dependent variable (DV) is the appearance of the green slime on the shower
  3. The control variable (CV) are time taken to spray, the amount of spray
  4. The experimental group (EG) is the side of the shower sprayed with lemon juice mixture
  5. The control group (CG) is the side of the shower sprayed with water.

INDEPENDENT VARIABLE

  • Independent variable is the variable of an experiment that is changed by the experimenter in order to bring about a change. It is the variable being tested in the experiment. In this case, the IV is the lemon juice mixture tested on the green slime on the shower.

DEPENDENT VARIABLE:

  • Dependent variable is the variable that is observed or measured in an experiment. It is also called responding variable. The DV in this case is the appearance of the green slime on the shower.

CONTROL VARIABLE:

  • Control variable is the variable that is kept constant throughout the experiment for all groups. The CV is the same for all the groups and they include: time taken to spray, the same amount of spray

CONTROL GROUP

  • Control group is the group that does not receive the independent variable or test in an experiment. In this case, the CG is the side of the shower sprayed with water.

EXPERIMENTAL GROUP:

  • Experimental group is the group of ab experiment that receives the experimental treatment or independent variable. In this case, the EG is the side of the shower sprayed with lemon juice mixture.

Therefore, the IV, DV, CV, EG and CG of this experiment are as follows:

  1. The independent variable (IV) is the lemon juice mixture
  2. The dependent variable (DV) is the appearance of the green slime on the shower
  3. The control variable (CV) are time taken to spray, the amount of spray
  4. The experimental group (EG) is the side of the shower sprayed with lemon juice mixture
  5. The control group (CG) is the side of the shower sprayed with water.

Learn more: brainly.com/question/17498238?referrer=searchResults

7 0
3 years ago
HELP PLEASE!! (100 points)
MrRa [10]

Answer:

As you cool a matter to absolute zero, their kinetic energy reduces significantly and the molecules slows down and begins to aggregate together. ... As heat is added, the molecules gain more kinetic energy. This shown in their increase motion. When heat is withdrawn, the particles slows down hope this helped

3 0
2 years ago
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