Answer:
Percentage dissociated = 0.41%
Explanation:
The chemical equation for the reaction is:

The ICE table is then shown as:

Initial (M) 1.8 0 0
Change (M) - x + x + x
Equilibrium (M) (1.8 -x) x x
![K_a = \frac{[C_3H_6ClCO^-_2][H^+]}{[C_3H_6ClCO_2H]}](https://tex.z-dn.net/?f=K_a%20%20%3D%20%5Cfrac%7B%5BC_3H_6ClCO%5E-_2%5D%5BH%5E%2B%5D%7D%7B%5BC_3H_6ClCO_2H%5D%7D)
where ;


Since the value for
is infinitesimally small; then 1.8 - x ≅ 1.8
Then;




Dissociated form of 4-chlorobutanoic acid = 
Percentage dissociated = 
Percentage dissociated = 
Percentage dissociated = 0.4096
Percentage dissociated = 0.41% (to two significant digits)
Answer:
2
Explanation:
Since it has to be 2H2+02→2H20 for it to be balanced.
heating is repeated to ensure all water molecules have evaporated
C. 2 hydrogen (H) atoms because in bonding with them sulfur will get a full valence shell and hydrogen will have a full valence shell.
KCl and PbCl2 both are salts having the same white color, however, potassium salts are soluble in water while lead salts are not.
This means that KCl is soluble in water while PbCl2 is not.
So, to distinguish between them, add the same amount of each salt in a beakers containing water (each salt in a separate beaker of course), ans shake the beaker or steer it.
The salt that dissolves in water would be KCl while the salt that doesn't dissolve in water would be PbCl2.