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qwelly [4]
3 years ago
9

an apple pie needs 10 large apples, 2 crusts (top and bottom), one tablespoon of cinnamon. write a balanced equation that fits t

his situation. how many apples are needed to make 25 pies?

Chemistry
2 answers:
laila [671]3 years ago
7 0

Answer:

Equation: 1 apple pie = 10 apples + 2 crusts + 1 tablespoon of cinnamon.

You will need 250 apples to make 25 pies.

Explanation:

Hi to answer this question we have to analyze the information given:

<em>Apple pie: </em>

  • <em>10 large apples </em>
  • <em>2 crusts </em>
  • <em>1 tablespoon of cinnamon  </em>

So, the equation for 1 apple pie would be:

1 apple pie = 10 apples + 2 crusts + 1 tablespoon of cinnamon  

For 25 pies, we simply multiply each side of the equation by 25:

25 x (1 apple pie) = 25x (10 apples + 2 crusts + 1 tablespoon of cinnamon )

25 apple pies = 250 apples + 50 crusts + 25 tablespoons of cinnamon)

So, you will need 250 apples to make 25 pies.

nasty-shy [4]3 years ago
4 0
You're answer is 250 apples for 25 pies
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3 years ago
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snow_lady [41]

Answer:

1. Mass of KCl produced = 774.8 g of KCl

2. Mass of KNO₃ produced = 13.837g

3. Moles of NaOH made = 0.846 moles

4. Moles of LiCl produced = 0.846 moles

5. Moles of CO₂ produced = 207.6 moles

Explanation:

1. From the equation of reaction, 1 mole of ZnCl₂ produces, 2 moles of KCl.

5.02 moles of ZnCl₂ will produce, 2 × 5.02 moles of KCl = 10.4 moles of KCl

Molar mass of KCl = (39 + 35.5) g/mol = 74.5 g/mol

10.4 moles of KCl = 10.4 × 74.5 g

Mass of KCl produced = 774.8 g of KCl

2. Mole ratio of KNO₃ and KOH = 1:1

O.137 moles of KOH will produce 0.137 moles of KNO₃

Molar mass of KNO₃ = 101 g/mol

Mass of KNO₃ produced = 0.137 × 101 g = 13.837g

3. Molar mas of Ca(OH)₂ = 74.0 g

Moles of Ca(OH)₂ in 31.3 g = 31.3/74.0 = 0.423 moles of Ca(OH)₂

Mole ratio of NaOH and Ca(OH)₂ in the reaction = 2 : 1

Moles of NaOH made = 2 × 0.423 = 0.846 moles

4. Molar mass of MgCl₂ = 95.0 g

Moles of MgCl₂ in 40.2 g = 40.2/95.0 = 0.423 moles

From the reaction equation, mole ratio of MgCl₂ and LiCl = 1:2

Moles of LiCl produced = 2 × 0.423 = 0.846 moles

5. From the equation of reaction, 1 mole of C₆H₁₀O₅ produces 6 moles of cO₂

34.6 moles of C₆H₁₀O₅ will produce 34.6 × 6 moles of CO₂

Moles of CO₂ produced = 207.6 moles

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