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zhannawk [14.2K]
3 years ago
14

Does the mass of water increase or decrease when it changes to ice

Chemistry
2 answers:
Ksivusya [100]3 years ago
6 0

Answer:

No, weight will not(and cannot)change.

Explanation:

it's just changes its physical appearance not its weight.

NikAS [45]3 years ago
4 0

Answer:

The mass stays the same only volume changes, the volume decreases

Explanation:

The ice shrinks (decreases volume) and becomes more dense. The weight will not (and cannot) change.

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Could you guys help me with these questions pls. Thank you
lapo4ka [179]

Answer:

8.4) 27.1 cm³

8.5) 0.217 mol/dm³

Explanation:

Please see attached picture for full solution.

8.4) Since the results from titrations 3-5 are within 0.10cm³ from each other, these 3 results are concordant.

8.5) Find mol of sulfuric acid to find mol of NaOH using mole ratio. Equation has already been balanced for you, so mole ratio of NaOH to H2S04 is 2:1. To find concentration of NaOH, divide the number of moles by the volume in dm³ since the units for concentration is mol/dm³, which you can think of as the number of moles of NaOH in a dm³ of solution.

1 dm³ = 1000cm³

Thus, 1cm³= 1/1000 dm³

3 0
3 years ago
Na(s)+H2O(l)-- NaoH(aq)+H2(g
Iteru [2.4K]

Answer:

whats the question?????????????

8 0
3 years ago
The molecular weight of an ionic compound is 118.9 g/mol. the ions in the unknown are sodium, oxygen, and bromine. what is the n
vodka [1.7K]
Answer is: the name of the unknown oxyanion is hypobromite.
<span>
M(NaBrO</span>ₓ) = 118.9 g/mol; <span>molecular weight of an ionic compound.
</span>M(Na) = 23 g/mol; atomic weight of sodium.
M(Br) = 79.9 g/mol; atomic weight of bromine.
M(O) = 16 g/mol; atomic weight of oxygen.
M(Na) + M(Br) + M(O) = 23 g/mol + 79.9 g/mol + 16 g/mol.
M(Na) + M(Br) + M(O) = 118.9 g/mol, so compound is NaBrO and oxyanion is BrO⁻.
7 0
4 years ago
How many grams of C are in 500g or NaHCO3​
harina [27]

Answer: 71.43g

Explanation: The RMM of NaHCO3 is

23+1+12+16(3)=84.

There is one carbon in NaHCO3 thus there are 1×12g of C in NaHCO3.

Thus

85gNaHCO3-----12g C

500gNaHCO3---- xgram

(500×12)÷84= 71.43

7 0
3 years ago
Instant cold packs, often used to ice athletic injuries on the field, contain ammonium nitrate and water separated by a thin pla
Zepler [3.9K]

Answer:

26.08 kJ

Explanation:

An endothermic reaction occurs when the heat is absorbed by the system, it means that it's a positive heat, and consequently, the enthalpy change will be positive too. Because that isn't happening a phase change, the heat transferred is sensitive, and it can be calculated by:

Q = m*c*ΔT

Where Q is the heat, m is the mass of the water (because the change is happening in it), c is the specific heat of water, and ΔT is the temperature change (final - initial).

m = volume*density

m = 25.00 mL * 1 g/mL

m = 25 g

The water is losing heat, so for it, the heat must be negative, because it will be an exothermic process. The heat for the reaction will be the same that is lost by water because the energy must be conserved (first law of thermodynamics):

Q = 25*4.18*(21.9 - 25.8)

Q = - 407.55 J

Q = + 407.55 J (for the endothermic reaction given)

The enthalpy change is the heat divided by the number of moles of the substance that is dissolved. The molar mass of NH₄NO₃ is:

2*14 g/mol of N + 4*1 g/mol of H + 3*16 g/mol of O = 80 g/mol

The number of moles is the mass divided by the molar mass:

n = 1.25/80

n = 0.015625

So, the change in enthalpy is:

ΔH = + 407.55/0.015625

ΔH = 26,083.2 J

ΔH = 26.08 kJ

6 0
3 years ago
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