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ycow [4]
3 years ago
14

8=14n will give Brainly

Mathematics
2 answers:
Marina CMI [18]3 years ago
4 0

Answer:

n = 4/7

Step-by-step explanation:

Step 1: Write equation

8 = 14n

Step 2: Divide both sides by 14

n = 8/14

Step 3: Simplify

n = 4/7

weqwewe [10]3 years ago
3 0
It equals 4/7 in fraction form and 0.57 in decimal form
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28^2-19^2= 423
Square root of 423 = 20.5669638

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Mark orders food for a restaurant. He orders 5 times the number of pounds of chicken as he does beef, and he orders 4 times the
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3 years ago
Can someone help me simplify (2n + 2) + (8 + 8)
emmasim [6.3K]

Answer:

7

Step-by-step explanation:

1. Lets Combine Like Terms. The only combineable terms are 8 and 8. So if we combine them they will equal 16. And we will have (2n+2)=16

2. Let's isolate the variable. We can do this by subtracting 2 from both sides. This will come out to 2n+14.

3. Let's further isolate the variable. We can do this by dividing both sides by two, which will finally come out to n=7

3 0
3 years ago
A survey of 25 young professionals fond that they spend an average of $28 when dining out, with a standard deviation of $10. (a)
skad [1K]

Answer:

a) The 95% of confidence intervals for the average spending

(23.872 , 32.128)

b) The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.

The null hypothesis is accepted

A survey of 25 young professionals statistically that the population mean is less than $30

<u>Step-by-step explanation</u>:

Step:-(i)

Given data a survey of 25 young professionals fond that they spend an average of $28 when dining out, with a standard deviation of $10

The sample size 'n' = 25

The mean of the sample   x⁻  = $28

The standard deviation of the sample (S) = $10.

Level of significance ∝=0.05

The degrees of freedom γ =n-1 =25-1=24

tabulated value t₀.₀₅ = 2.064

<u>Step 2:-</u>

The 95% of confidence intervals for the average spending

((x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )

(28 - 2.064 \frac{10}{\sqrt{25} } ,28 + 2.064\frac{10}{\sqrt{25} } )

( 28 - 4.128 , 28 + 4.128)

(23.872 , 32.128)

a) The 95% of confidence intervals for the average spending

(23.872 , 32.128)

b)

Null hypothesis: H₀:μ<30

Alternative Hypothesis: H₁: μ>30

level of significance ∝ = 0.05

The test statistic

t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }

t = \frac{28-30 }{\frac{10}{\sqrt{25} } }

t = |-1|

The calculated value t= 1< 1.711( single tailed test) at 0.05 level of significance with 24 degrees of freedom.

The null hypothesis is accepted

<u>Conclusion</u>:-

The null hypothesis is accepted

A survey of 25 young professionals statistically that the population mean is less than $30

8 0
3 years ago
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