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2 years ago

6

As the frequency of a wave increases the wavelength.

2 answers:

xxMikexx [17]2 years ago

6 0

As the frequency increases the wave length gets shorter

And again as the frequency decreases the wavelength gets longer

zaharov [31]2 years ago

4 0

Answer:

decreases

Explanation:

Remeber:

There is always inverse relation between frequency and wavelength.

So if one of them increases, other decreases and vice-versa.

f ∝ 1 / λ

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SVETLANKA909090 [29]

Explanation:

For example, when a drum is struck, the flexible skin (sometimes called a membrane) of the drum vibrates. The compression and expansion of the air on either side of the vibrating membrane produces differences in air pressure. The pressure differences generate a sound wave that propagates outward from the drum surface.

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3 years ago

What is the distance from the crest to the equilibrium of a wave called? A. amplitude B. period C. frequency D. phase

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its the first one. A.

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3 years ago

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Four point masses of 3.0 kg each are arranged in a square on masslessrods. The length of a side of the square is 0.50m. What is

Zigmanuir [339]

Answer:

Part a)

$I = 1.5 kg m^2$

Part b)

$I = 0.75 kg m^2$

Part c)

$I = 1.5 kg m^2$

Explanation:

Part a)

Moment of inertia of the system about an axis passing through B and C is given as

$I = mL^2 + mL^2 + m(0) + m(0)$

$I = 2mL^2$

$I = 2(3 kg)(0.50^2)$

$I = 1.5 kg m^2$

Part b)

Moment of inertia of the system about an axis passing through A and C is given as

$I = m(0^2) + m(\frac{L}{\sqrt2})^2 + m(0) + m(\frac{L}{\sqrt2})^2$

$I = 2m\frac{L^2}{2}$

$I = (3 kg)(0.50^2)$

$I = 0.75 kg m^2$

Part c)

Moment of inertia of the system about an axis passing through the center of the square and perpendicular to the plane of the square

$I = m(\frac{L}{\sqrt2})^2 + m(\frac{L}{\sqrt2})^2 + m(\frac{L}{\sqrt2})^2 + m(\frac{L}{\sqrt2})^2$

$I = 4m\frac{L^2}{2}$

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3 years ago

An iron railroad rail is 700 ft long when the temperature is 30°C. What is its length when the temperature is – 10°C?

MAVERICK [17]

Answer:

699.67ft

Explanation:

We are given with,

α = 1.2×10⁻⁵ / °C
L₀ = 700 ft
ΔT = -10°C − 30°C = -40°C

Now, We have to find ΔL:

ΔL = (1.2×10⁻⁵ / °C) (700 ft) (-40°C)
ΔL = −0.336

Rounded to two significant figures, the change in length is −0.33ft.

<u>Therefore, the final length is approximately 700 ft − 0.33 ft = 699.67ft</u>.

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3 years ago

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Kobotan [32]

Answer:

A. constructive interference.

Explanation:

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3 years ago