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Brrunno [24]
2 years ago
7

In the following circuit (Fig.3), calculate the intensity I through the resistance 3 using the principle of superposition.

Physics
1 answer:
crimeas [40]2 years ago
6 0

Answer:

time

Explanation:

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0.5 kg air hockey puck is initially at rest. What will it’s kinetic energy be after a net force of .8 N acts on it for a distanc
weqwewe [10]

Answer:

1.6 J

Explanation:

Work = change in energy

W = ΔKE

Fd = KE

(0.8 N) (2 m) = KE

KE = 1.6 J

4 0
3 years ago
Initial velocity 10 m/s accelerates at 5 m/s for 2 seconds whats the final velocity
stiks02 [169]

Answer:

<em>The final velocity is 20 m/s.</em>

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

Being a the constant acceleration, vo the initial speed, and t the time, the final speed can be calculated as follows:

v_f=v_o+at

The provided data is: vo=10 m/s, a=5\ m/s^2, t=2 s. The final velocity is:

v_f=10~m/s+5\ m/s^2\cdot 2\ s

v_f=20\ m/s

The final velocity is 20 m/s.

8 0
3 years ago
In an Atwood's machine, one block has a mass of 602.0 g, and the other a mass of 717.0 g. The pulley, which is mounted in horizo
Wittaler [7]

Answer:

The acceleration of the both masses is 0.0244 m/s².

Explanation:

Given that,

Mass of one block = 602.0 g

Mass of other block = 717.0 g

Radius = 1.70 cm

Height = 60.6 cm

Time = 7.00 s

Suppose we find  the magnitude of the acceleration of the 602.0-g block

We need to calculate the acceleration

Using equation of motion

s=ut+\dfrac{1}{2}at^2

Where, s = distance

t = time

a = acceleration

Put the value into the formula

60.0\times10^{-2}=0+\dfrac{1}{2}\times a\times(7.00)^2

a=\dfrac{60.0\times10^{-2}\times2}{(7.00)^2}

a=0.0244\ m/s^2

Hence, The acceleration of the both masses is 0.0244 m/s².

5 0
3 years ago
Two identical 0.400 kg masses are pressed against opposite ends of a light spring of force constant 1.75 N/cm, compressing the s
nlexa [21]

Answer:

0.853 m/s

Explanation:

Total energy stored in the spring = Total kinetic energy of the masses.

1/2ke² = 1/2m'v².................... Equation 1

Where k = spring constant of the spring, e = extension, m' = total mass, v = speed of the masses.

make v the subject of the equation,

v = e[√(k/m')].................... Equation 2

Given: e = 39 cm = 0.39 m, m' = 0.4+0.4 = 0.8 kg, k = 1.75 N/cm = 175 N/m.

Substitute into equation 2

v = 0.39[√(1.75/0.8)

v = 0.39[2.1875]

v = 0.853 m/s

Hence the speed of each mass = 0.853 m/s

7 0
3 years ago
Do the rock layers from the various locations that you investigated record evidence of an asteroid impact on Earth? Make a CLAIM
KiRa [710]

Answer:

Drilling into the seafloor off Mexico, scientists have extracted a unique geologic record of the single worst day in the history of life on Earth, when a city-sized asteroid smashed into the planet 65 million years ago, wiping out the dinosaurs and three-quarters of all other life.

Their analysis of these new rock samples from the Chicxulub crater, made public Monday, reveals a parfait of debris deposited in layers almost minute-by-minute at the heart of the impact during the first day of a global catastrophe. It records traces of the explosive melting, massive earthquakes, tsunamis, landslides and wildfires as the immense asteroid blasted a hole 100 miles wide and 12 miles deep, the scientists said.

8 0
3 years ago
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