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2 years ago

How do I find the radius from the circumference of a circle

Mathematics

1 answer:

Sophie [7]2 years ago

7 0

Answer:

Just remember to divide the diameter by two to get the radius. If you were asked to find the radius instead of the diameter, you would simply divide 7 feet by 2 because the radius is one-half the measure of the diameter. The radius of the circle is 3.5 feet.

Step-by-step explanation:

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A store is selling five cans of tomato sauce for $5.25. What is the unit price? unit price = total price ÷ number of units per p

aleksklad [387]

Answer: Option A

$P = \$\ 1.05$

Step-by-step explanation:

If we have 5 cans of ketchup they cost $ 5.25. Then the unit price of cans is what each can costs individually.

The unit price should then be less than $ 5.25, and that is the price for 5 cans and we want to know the price for just one can of ketchup.

Then to calculate the price of each can divide the price of the 5 cans by 5.

$P = \frac{5.25}{5}$

$P = \$\ 1.05$

8 0

2 years ago

Please hurry I kinda late ;)

sertanlavr [38]

I think it’s the second one
Hope that helped

6 0

2 years ago

X+ x^2+x^3<br> What is the answer?

Oksana_A [137]

Answer:

x(1+x+x^2)

Step-by-step explanation:

3 0

3 years ago

How do I write in standard form 700000 + 20000 + 4000 + 500 + 60 + 2

Inga [223]

All you have to do is just bring the numbers that are not zero from each digit.

so in this process, the answer you would get is 724,562.

I hope this helped

5 0

3 years ago

Read 2 more answers

Create triangle A’B’C by reflecting triangle ABC over the y-axis on the coordinate plane. What are the new coordinates of the ve

pickupchik [31]

Answer:

Step-by-step explanation:

When talking about reflection, we usually mean reflecting across a line, or axis. Reflecting a shape means looking at the mirror image on the other side of the axis. Consider the point (x,y), if you reflect this point across the y-axis you should multiply the x-coordinate by -1, so you get:

$(x,y)\rightarrow(-x,y)$

For triangle ABC we have:

$A(-4,2) \\ \\ B(-1,3) \\ \\ C(-1,-4)$

Therefore, the reflecting points are:

$A'(4,2) \\ \\ B(1,3) \\ \\ C(1,-4)$

Both the original triangle and the reflected one are shown below.

8 0

3 years ago