Part A
F = 50 N is the force applied along the purple vector
r = 1.5 is the radius (half the diameter 3)
theta = 110 is the angle in which the force vector is applied
Use this formula to plug in the values to find the torque T
T = F*r*sin(theta)
T = 50*1.5*sin(110)
T = 70.4769
<h3>Answer: The torque applied is approximately 70.4769 Newton-meters</h3>
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Part B
Refer back to the formula in part A. If theta is the variable, then T maxes out when theta = 90 degrees, because sin(theta) is maxed out at 1 here. If theta = 90, then T = F*r. The torque is maxed out when the force vector is perpendicular to the original position vector, this way you get the most push leading to the highest twisting or turning force possible.
<h3>Answer: 90 degrees</h3>
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Part C
Use the values from part A, but make theta = 90 so that the torque T is maxed out. So we would get the following
T = F*r*sin(theta)
T = 50*1.5*sin(90)
T = 50*1.5*1
T = 75
<h3>Answer: The max torque possible is 75 Newton-meters</h3>
If someone had an equation that was in slope intercept form, the y intercept and slope are easily accessible and easily calculable.
<span>Then, if someone had a line that was in slope intercept form, then they would probably choose to use the y intercept and slope to graph that line.
</span>
Answer:
1.65
Step-by-step explanation:
0.99/3 = .33
.33 x 5 = $1.65
Answer:
9/2
Step-by-step explanation:
(3, -20) & (11, 16)
To find the slope of the line that passes through these points, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)
Plug in these values:
(16 - (-20)) / (11 - 3)
Simplify the parentheses.
= (36) / (8)
Simplify the fraction.
36/8
= 9/2
9/2 is the most simplified fraction. This is your slope.
Hope this helps!
Yes that is one way. You can also prove that a shape is a square by looking at the angles and each side are congruent to each other
