You are throwing a stone straight-up in the absence of air friction. The stone is caught at the same height from which it was th
1 answer:
Answer:
A. True
Explanation:
When a stone is thrown straight-up, it has an initial velocity which decreases gradually as the stone move to maximum height due to constant acceleration due to gravity acting downward on the stone, at the maximum height the final velocity of the stone is zero. As the stone descends the velocity starts to increase and becomes maximum before it hits the ground.
Height of the motion is given by;
g is acceleration due to gravity which is constant
H is height traveled
u is the speed of throw, which determines the value of height traveled.
Therefore, when the stone is caught at the same height from which it was thrown in the absence of air resistance, the speed of the stone when thrown will be equal to the speed when caught.
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Answer:
d=510.2m
t=10.2s
Explanation:
The formulas for accelerated motion are:
From them we can get .
We have:
And substitute:
We multiply both sides by 2a, and continue:
Being d the displacement , we have
For our exercise, we will write this as:
And taking upwards direction positive and imposing final velocity 0m/s (for maximum height), we have:
For the time we use:
Answer:
d = 27.7 m
Explanation:
Here the car is driving on the inclined plane
So here we can say that work done by the gravity and work done by friction is equal to change in kinetic energy of the system
So here we can write it as
now we have
m = 1700 kg