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ollegr [7]
3 years ago
8

You are throwing a stone straight-up in the absence of air friction. The stone is caught at the same height from which it was th

rown. the speed of the stone when thrown is equal to the speed when caught.A. TrueB. False
Physics
1 answer:
balu736 [363]3 years ago
7 0

Answer:

A. True

Explanation:

When a stone is thrown straight-up, it has an initial velocity which decreases gradually as the stone move to maximum height due to constant acceleration due to gravity acting downward on the stone, at the maximum height the final velocity of the stone is zero. As the stone descends the velocity starts to increase and becomes maximum  before it hits the ground.

Height of the motion is given by;

H = \frac{u^2}{2g}

g is acceleration due to gravity which is constant

H is height traveled

u is the speed of throw, which determines the value of height traveled.

Therefore, when the stone is caught at the same height from which it was thrown in the absence of air resistance, the speed of the stone when thrown will be equal to the speed when caught.

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4. Johnny exerts a 3.55 N rightward force on a 0.200-kg box to accelerate it across a low-friction track. If the total resistanc
Anon25 [30]

a) 15.2 m/s^2

b) 1.96 N

c) 1.96 N

Explanation:

a)

To find the box's acceleration, we have to find first the net force acting on the box in the horizontal direction.

We have:

- The forward force of 3.55 N

- The backward, resistive force of 0.52 N

So, the net force forward is

\sum F=3.55-0.52=3.03 N

Now we can find the acceleration by using Newton's second law of motion, which states that:

\sum F=ma

where

m = 0.200 kg is the mass of the box

a is its acceleration

And solving for a, we find the acceleration:

a=\frac{\sum F}{m}=\frac{3.03}{0.200}=15.2 m/s^2

b)

The gravitational force on an object is the force with which the object is pulled towards the ground by the Earth.

It is given by

W=mg

where

m is the mass of the object

g is the gravitational field strength

In this problem we have

m = 0.200 kg is the mass of the box

g=9.8 m/s^2 is the gravitational field strength

So, the gravitational force on the box is

W=(0.200)(9.8)=1.96 N

c)

The normal force is the reaction force exerted by the floor on the box, in the upward direction.

In order to find the magnitude of this force, we apply Newton's second law of motion along the vertical direction.

We have two forces in this direction:

- The gravitational force, W, downward

- The normal force, N, upward

So the net force is

\sum F=N-W

According to Newton's second law,

\sum F=ma

However, the box is at rest in the vertical direction, so the vertical acceleration is zero:

a=0

This means that the net force is zero:

\sum F=0

And so, we can find the normal force:

N-W=0\\N=W=1.96 N

4 0
3 years ago
A conservative force on a particle moving along the x axis is given by F = (3x^2-2x)i. Which of the following is a potential tha
ANTONII [103]

pck u

report me if you can

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5 0
2 years ago
a spring length of 20cm, the vibrational frequency of the spring is 15 Hz, about that spring period is?
nlexa [21]
I gave u something that mite help

5 0
3 years ago
Occurs when air traveling over land moves over water, cools down, and travels back over the land
Neporo4naja [7]

The answer is sea breeze. Good luck!

8 0
3 years ago
"A magnet with a red end and blue end is tied to a string and suspended from the ceiling. The red end is found to orient northwa
Oksanka [162]

Answer:

If we consider the north pole of the earth as the north pole of the magnet in the nucleus of the earth, we have to consider that the the magnet with the red end is a magnetic southpole (because opposite poles try to get closer). Consequently, the green end is magnetic northpole and the yellow end is a magnetic southpole.

Hence, the answer  is

B. Southpole

I hope this is useful for you,

Regards

6 0
3 years ago
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