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denpristay [2]
2 years ago
5

A wire is joined to points X and Y in the circuit diagram shown. A diagram of a circuit with a power source on the left. Directl

y above the power source is a dot labeled X and then a circle with an X in it. The circuit then splits with one path straight back to the power source and the other path has 3 circles with X in them labeled 2, 3, and 4 respectively. There is a point labeled Y between circles 2 and 3.A diagram of a circuit with a power source on the left. Directly above the power source is a dot labeled X and then a circle with an X in it. After the x are 4 different circles on the circuit with Xs in them labeled 1, 2, 3, and 4 respectively. There is a point labeled Y in between circles 2 and 3. There is a branch of the circuit from X to Y. How does the circuit change when the wire is added? A closed circuit occurs and makes all bulbs turn off. An open circuit occurs and makes all bulbs turn off. A short circuit occurs and makes bulbs 3 and 4 turn off but keeps bulbs 1 and 2 lit. A short circuit occurs and makes bulbs 1 and 2 turn off but keeps bulbs 3 and 4 lit.
Physics
1 answer:
tino4ka555 [31]2 years ago
7 0

Answer:

c thats the answer yep

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3 0
3 years ago
A ball tossed vertically upward from the ground next to a building passes the bottom of a window 1.8 s after being tossed and pa
VLD [36.1K]

The ball takes 0.2 sec to travel the height of the window, which is 2 m.

 Then the speed of the ball at that time was

v = \frac{d}{t}

v = \frac{2}{0.20}

v = 10\ \frac{m}{s}

We know that:

v = v_0 -gt

Where v_0 is the initial velocity.

So:

10 = v_0 -9.8(2)

10 + 9.8(2) = v_0

v_0 = 29.6\ m / s

Then we have the equation for the position as a function of time.

r = r_0 + v_0t - \frac{1}{2}gt^2

Where

r_0 = initial position

r = position as a function of time

v_0 = initial velocity

g = acceleration of gravity

t = time.

If the ball is thrown from the ground then:

r_0 = 0 m

We want to find now the distance between the window and the ground.

When the ball reaches the bottom of the window t = 1.8s

So:

r = 0 + 29.6(1.8) - 0.5(9.8)(1.8)^2

r = 37,404 m

The window is 37,404 m high

Finally, to know how high the ball rises we must know at what moment the vertical velocity of the ball is zero.

v = v_0 -gt\\\\0 = v_0 -gt\\\\gt = v_0\\\\t = \frac{29.6}{9.8}

t = 3.02\ s

Now we replace t in the position equation

r = 0 + 29.6(3.02) -0.5(9.8)(3.02)^2

r = 44.70\ m

The ball reaches up to 44.70 m in height.

3 0
3 years ago
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just olya [345]
The answer is B electrons will be rubbed from one surface to another
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PolarNik [594]

Answer:

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Explanation:

7 0
3 years ago
A camera lens used for taking close-up photographs has a focal length of 22.0 mm. The farthest it can be placed from the film is
Arada [10]

Answer:

p = 6.64 cm

Explanation:

For this exercise we use the equation of the constructor

          \frac{1}{f} = \frac{1}{p} + \frac{1}{q}

where f is the focal length, p and q are the distance to the object and the image, respectively

They tell us the focal length f = 2.2 cm and that the image as far as it can go is q = 3.29 cm, let's find the position of the object that creates this image

          \frac{1}{p} = \frac{1}{f} - \frac{1}{q}

          1 / p = 1 / 2.2 - 1/3.29

           1 / p = 0.15059

           p = 6.64 cm

therefore the farthest distance from the object is 6.64 c

3 0
3 years ago
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