Answer:
3°C
Explanation:
We can that heat Q=m
dT
Where m is the mass
= specific heat capacity
dT = Temperature difference
here we have given m=625 g =.625 kg
specific heat of granite =0.79 J/(g-K) = 0.79 KJ/(kg-k)
=25°C
we have to find
we have also given Q=10.9 KJ
10.9=0.625×0.79×(25-
)
25-
=22
=3°C
Answer
22.5 m/s
Explanation
We shall use the trigonometric ratio cosine to find the horizontal component.
cos = adjacent/hypotenuse
Adjacent is the horizontal and hypotenuse is the fly speed.
cos 30° = horizontal / 26
horizontal velocity = 26 × cos 30°
= 26 × 0.866
= 22.5166
= 22.5 m/s
Answer:
38.3 m/s
Explanation:
To find vertical component of initial velocity, you'd have to use sine ratio:

is vertical component of initial velocity and
is initial velocity given which is 50 m/s.
A stone is projected at an angle of 50 degrees so
= 50°. Substitute in the formula:

Therefore, the vertical component of initial velocity is approximately 38.3 m/s
(The picture is also attached for visual reference!)
Answer:
They both have the same angular speed.
Explanation:
The mathematical formula for angular speed is:

where
is angular speed,
is a constant, and
is the period (the time it takes the marry-go-round to complete a lap).
What we can see from the formula is that, since the
does not change its value, the angular speed depends only on the period T.
In this case for both the children closer to the outher edge and for the children closer to the center, the time to complete a lap is the same, because the time does not depend on where they are sitting in the marry go round. This means that the period for both is the same.
Thus, since the period for both is the same, the angular speed given by
will also be the same
Answer:
T=0.372 s, f=2.7 Hz, w=16.9 rad/s, k=179.2 N/m, v= 8.78 m/s, F= 48.4 N
Explanation:
a.)
Period: It is already given in the question "oscillator repeats its motion every 0.372 s".
So T=0.372 s
b)
frequency= f = 1/ T
f = 1/ 0.372
f=2.7 Hz
c).
Angular frequency= w= 2πf
w= 2*π*2.7
w=16.9 rad/s
d)
Spring Constant:
As w=
⇒w²= k/m
⇒k= m*w²
⇒k= 0.628 * 16.9² N/m
⇒k=179.2 N/m
e)
The mass will have maximum speed when it passes through the mean position.
At mean position
Maximum elastic potential energy = Maximum kinetic energy
1/2 k A² = 1/2 m v² ( A is amplitude of oscillation)
⇒ v=
⇒ v=
\
⇒ v= 8.78 m/s
f)
Maximum force will be exerted on the block when it is at maximum distance.
F= k* A ( A is amplitude of oscillation)
F= 179.2 * 0.27 N
F= 48.4 N