Answer : The cell emf for this cell is 0.077 V
Solution :
The balanced cell reaction will be,
Oxidation half reaction (anode):
Reduction half reaction (cathode):
In this case, the cathode and anode both are same. So, is equal to zero.
Now we have to calculate the cell emf.
Using Nernest equation :
where,
n = number of electrons in oxidation-reduction reaction = 2
= ?
= 0.0111 M
= 4.50 M
Now put all the given values in the above equation, we get:
Therefore, the cell emf for this cell is 0.077 V
Accelerating pretty sure but be sure to double check the answer
Normal force, weight, Kinetic friction, and air resistance are a few I think of the top of my head.
I hope this helps
The box is accelerated from rest to 4 m/s in a matter of 2.5 s, so its acceleration <em>a</em> is such that
4 m/s = <em>a</em> (2.5 s) → <em>a</em> = (4 m/s) / (2.5 s) = 1.6 m/s²
Then the force applied to the box has a magnitude <em>F</em> such that
<em>F</em> = (10 kg) (1.6 m/s²) = 16 N
Answer: True.
Explanation:
You would be able to visualize the basketballs height going up and when it sinks down into the hoop.