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LenKa [72]
3 years ago
12

The rotor of a helicopter is gaining angular speed with constant angular acceleration. At tt = 0 it is rotating at 1.25 rad/srad

/s. From tt = 0 to tt = 2.00 ss, the rotor rotates through 8.00 radrad. What is the angular acceleration of the rotor?
Physics
1 answer:
lara31 [8.8K]3 years ago
4 0

Answer:

2.75\ rad/s^2

Explanation:

\omega_i = Initial angular velocity = 1.25 rad/s

\alpha = Angular acceleration

\theta = Angle of rotation = 8 rad

t = Time taken = 2 s

\theta=\omega_it+\frac{1}{2}\alpha t^2\\\Rightarrow 8=1.25\times 2+\frac{1}{2}\times \alpha\times 2^2\\\Rightarrow \alpha=\dfrac{2}{2^2}(8-1.25\times 2)\\\Rightarrow \alpha=2.75\ rad/s^2

The angular acceleration of the rotor is 2.75\ rad/s^2

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